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Solve each triangle. $$ A=110^{\circ}, \quad C=30^{\circ}, \quad c=3 $$

Short Answer

Expert verified
B = 40°, a ≈ 5.64, b ≈ 3.86

Step by step solution

01

Find the Missing Angle B

The sum of the angles in a triangle is always 180 degrees. Use the formula: \[ B = 180^\text{°} - A - C \] Substitute the given values: \[ B = 180^\text{°} - 110^\text{°} - 30^\text{°} \]Calculate the result: \[ B = 40^\text{°} \]
02

Use the Law of Sines to Find Side a

Use the Law of Sines formula: \[ \frac{a}{\text{sin}(A)} = \frac{c}{\text{sin}(C)} \] Rearranging to solve for a: \[ a = c \left( \frac{\text{sin}(A)}{\text{sin}(C)} \right) \] Substitute the given values: \[ a = 3 \left( \frac{\text{sin}(110^\text{°})}{\text{sin}(30^\text{°})} \right) \]Calculate the result: \[ a \approx 5.64 \]
03

Use the Law of Sines to Find Side b

Again, use the Law of Sines formula: \[ \frac{b}{\text{sin}(B)} = \frac{c}{\text{sin}(C)} \] Rearranging to solve for b: \[ b = c \left( \frac{\text{sin}(B)}{\text{sin}(C)} \right) \] Substitute the given values: \[ b = 3 \left( \frac{\text{sin}(40^\text{°})}{\text{sin}(30^\text{°})} \right) \]Calculate the result: \[ b \approx 3.86 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Sines
The Law of Sines is a helpful theorem for solving triangles, especially when you know one side length and the opposite angle and seek another side length or angle in the triangle. The formula is: \ \frac{a}{\text{sin}(A)} = \frac{b}{\text{sin}(B)} = \frac{c}{\text{sin}(C)}, \ where \( a, b, \text{ and } c \) are the side lengths, and \( A, B, \text{ and } C \) are the respective opposite angles.

For the given triangle with angles \( A=110^\text{°}\) and \( C=30^\text{°} \), and side \( c=3 \):
  • Calculate side \( a \)
  • \ a = c \frac{\text{sin}(A)}{\text{sin}(C)} = 3 \frac{\text{sin}(110^\text{°})}{\text{sin}(30^\text{°})} \
  • Calculate side \( b \)
  • \ b = c \frac{\text{sin}(B)}{\text{sin}(C)} = 3 \frac{\text{sin}(40^\text{°})}{\text{sin}(30^\text{°})} \ This method, using proportions involving angles and the opposite sides, allows you to efficiently and accurately solve for the unknown sides.

    Always remember that you need at least one angle-side pair to use the Law of Sines. It becomes a powerful tool for non-right triangle calculations.
Angle Sum in a Triangle
The Angle Sum in a triangle always amounts to 180 degrees. This basic geometric principle helps determine a missing angle if you know the other two angles. For instance:

For the given triangle, where \( A=110^\text{°} \) and \( C=30^\text{°} \), the missing angle \( B \) is calculated by: \ B = 180^\text{°} - A - C = 180^\text{°} - 110^\text{°} - 30^\text{°} = 40^\text{°} \
  • This way, even if only two angles are known, the third angle is easily found.

This fundamental understanding leads to further applications, such as using the Law of Sines or other trigonometric principles to solve for sides or other angles. Make sure always to check your angle sum as a good practice to avoid calculation errors. For non-right triangles, especially, verifying the sum will ensure your other methods are on track.
Triangle Side Calculation
Triangle side calculation can be efficiently managed by combining fundamental principles such as the Law of Sines and the Angle Sum property. The basic steps are:
  • Determine the unknown angle.
  • Apply the Law of Sines as needed.

For our example:
  • First, found \( B=40^\text{°} \) using \( 180^\text{°} - A - C \).

Then, using the Law of Sines, to find side \( a \), we do: \ a = 3 \frac{\text{sin}(110^\text{°})}{\text{sin}(30^\text{°})} ≈ 5.64 \
  • Next, to find side \( b \):
  • \ b = 3 \frac{\text{sin}(40^\text{°})}{\text{sin}(30^\text{°})} ≈ 3.86 \
  • This step-by-step assignments of calculating one side and then another simplifies what may initially seem like complex tasks.

Solving triangles by using sound formulae such as the Law of Sines, combined with geometric properties, is better for a logical and straightforward learning process.

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Most popular questions from this chapter

The function \(d\) models the distance (in meters) of the bob of a pendulum of mass \(m\) (in kilograms) from its rest position at time \(t\) (in seconds) is given. The bob is released from the left of its rest position and represents a negative direction. (a) Describe the motion of the object. Be sure to give the mass and damping factor. (b) What is the initial displacement of the bob? That is, what is the displacement at \(t=0 ?\) (c) Graph the motion using a graphing utility. (d) What is the displacement of the bob at the start of the second oscillation? (e) What happens to the displacement of the bob as time increases without bound? $$ d(t)=-10 e^{-0.8 t / 50} \cos \left(\sqrt{\left(\frac{2 \pi}{3}\right)^{2}-\frac{0.64}{2500}} t\right) $$

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