Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The displacement \(d\) (in meters) of an object at time \(t\) (in seconds) is given. (a) Describe the motion of the object. (b) What is the maximum displacement from its rest position? (c) What is the time required for one oscillation? (d) What is the frequency? $$ d(t)=-9 \sin \left(\frac{1}{4} t\right) $$

Short Answer

Expert verified
The motion is simple harmonic. The maximum displacement is 9 meters. The period is 8\pi seconds and the frequency is 1/(8\pi) Hz.

Step by step solution

01

Understand the given function

The displacement function is given by \[ d(t) = -9 \sin \left( \frac{1}{4} t \right) \].This function describes a sinusoidal motion, indicating it is periodic.
02

Describe the motion of the object

Since the function is a sine function, the motion of the object is simple harmonic motion. The negative sign indicates that the motion starts in the opposite direction of the positive sine function.
03

Find the maximum displacement

The maximum value of \( \sin(x) \) is 1. Thus,\[ d(t) = -9 \cdot 1 = -9 \text{ meters} \].The maximum displacement from the rest position is 9 meters.
04

Calculate the time for one oscillation (period)

The period \(T\) of a sine function \( A \sin(Bt) \) is given by \( T = \frac{2\pi}{B} \). Here, \( B = \frac{1}{4} \). Thus,\[ T = \frac{2\pi}{\frac{1}{4}} = 8\pi \text{ seconds} \].
05

Determine the frequency

Frequency \( f \) is the reciprocal of the period. Thus,\[ f = \frac{1}{T} = \frac{1}{8\pi} \text{ Hz} \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sinusoidal function
A sinusoidal function is a mathematical function that describes a smooth and repetitive oscillation. It is often depicted as a sine or cosine wave.

If we look at the given function, \(d(t) = -9 \sin \left( \frac{1}{4} t \right)\), it directly reflects sinusoidal behaviour. Here, \(\sin(x)\) represents the sine function, which oscillates between -1 and 1 as its argument changes.

The negative sign in front of the sine function simply means that the wave is inverted or flipped upside down. This means that the motion starts in the opposite direction of a standard positive sine wave.

Sinusoidal functions are incredibly useful because they model periodic phenomena, such as sound waves, light waves, and even the motion of a pendulum or spring.
maximum displacement
Maximum displacement refers to the furthest point an object moves from its starting or rest position during oscillation.

In the given function \(d(t) = -9 \sin \left( \frac{1}{4} t \right)\), the maximum value \(\sin(x)\) can take is 1. Hence, the maximum displacement from the rest position is calculated as follows:
\( d(t) = -9 \cdot 1 = -9 \text{ meters}\).

Absolute displacement removes the negative sign to give an absolute value, meaning the object moves 9 meters away from the rest position at its peak. Maximum displacement is an important concept because it tells us the amplitude of the motion, indicating the energy involved in the movement.
oscillation period
The oscillation period is the time it takes for an object to complete one full cycle of motion from its starting point, back to that point.

For the function \(d(t) = -9 \sin \left( \frac{1}{4} t \right)\), the period \(T\) is given by the formula \( T = \frac{2\pi}{B} \).

Here \( B = \frac{1}{4} \), substituting this in gives:
\( T = \frac{2\pi}{\frac{1}{4}} = 8\pi \text{ seconds}\).

This means the object takes \(8\pi\) seconds to complete one oscillation.

Knowing the period is crucial because it helps in understanding the timing and rhythm of the system's movements, and is a fundamental property of any periodic motion.
frequency calculation
Frequency describes how often an oscillation repeats in one second. It is the reciprocal of the period and is measured in Hertz (Hz).

For the given function, knowing the period \(T = 8\pi\) seconds, we find the frequency using the relation:
\( f = \frac{1}{T} \text{ Hz}\).

So, our calculation is:
\( f = \frac{1}{8pi} \text{ Hz}\).

This very small frequency value indicates that each oscillation takes a substantial amount of time to complete. Understanding frequency is vital in many real-world applications, such as tuning musical instruments, designing circuits, and studying wave phenomena.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph the function \(f(x)=\frac{\sin x}{x}, x>0 .\) Based on the graph what do you conjecture about the value of \(\frac{\sin x}{x}\) for \(x\) close to \(0 ?\)

The Sawtooth Curve An oscilloscope often displays a sawtooth curve. This curve can be approximated by sinusoidal curves of varying periods and amplitudes. (a) Use a graphing utility to graph the following function, which can be used to approximate the sawtooth curve. $$ f(x)=\frac{1}{2} \sin (2 \pi x)+\frac{1}{4} \sin (4 \pi x) \quad 0 \leq x \leq 4 $$ (b) A better approximation to the sawtooth curve is given by $$ f(x)=\frac{1}{2} \sin (2 \pi x)+\frac{1}{4} \sin (4 \pi x)+\frac{1}{8} \sin (8 \pi x) $$ Use a graphing utility to graph this function for \(0 \leq x \leq 4\) and compare the result to the graph obtained in part (a). (c) A third and even better approximation to the sawtooth curve is given by \(f(x)=\frac{1}{2} \sin (2 \pi x)+\frac{1}{4} \sin (4 \pi x)+\frac{1}{8} \sin (8 \pi x)+\frac{1}{16} \sin (16 \pi x)\) Use a graphing utility to graph this function for \(0 \leq x \leq 4\) and compare the result to the graphs obtained in parts (a) and (b). (d) What do you think the next approximation to the sawtooth curve is?

Tuning Fork The end of a tuning fork moves in simple harmonic motion described by the function \(d(t)=a \sin (\omega t)\) If a tuning fork for the note A above middle \(\mathrm{C}\) on an even-tempered scale \(\left(A_{4},\right.\) the tone by which an orchestra tunes itself) has a frequency of 440 hertz (cycles per second), find \(\omega\). If the maximum displacement of the end of the tuning fork is 0.01 millimeter, find a function that describes the movement of the tuning fork.

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Determine whether \(x-3\) is a factor of \(x^{4}+2 x^{3}-21 x^{2}+19 x-3\)

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. If \(\cos \alpha=\frac{4}{5}, 0<\alpha<\frac{\pi}{2},\) find the exact value of: (a) \(\cos \frac{\alpha}{2}\) (b) \(\sin \frac{\alpha}{2}\) (c) \(\tan \frac{\alpha}{2}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free