Chapter 7: Problem 2
True or False If \(x=3\) is a vertical asymptote of the graph of a rational function \(R,\) then as \(x \rightarrow 3,|R(x)| \rightarrow \infty\).
Short Answer
Expert verified
True
Step by step solution
01
Understand the definition of a vertical asymptote
A vertical asymptote of a function occurs when the function's value approaches \(\text{either positive or negative infinity}\) as the input approaches a specific value from either the left or the right. For a rational function \( R(x) = \frac{P(x)}{Q(x)} \), where \(P(x) \) and \(Q(x)\) are polynomials, a vertical asymptote occurs when \( Q(x)=0 \) and \(P(x) \) does not equal zero at \(x = a\).
02
Identify the given conditions
It is given that \(x = 3\) is a vertical asymptote of the rational function \(R(x)\). This means that as \(x \rightarrow 3\), the function \(R(x)\) will tend towards \( \text{either positive or negative infinity} \), based on whether the function values on either side of \(x = 3\) approach very large positive or negative values.
03
Determine the implication of the asymptote
Since \(x = 3\) is a vertical asymptote, by definition, as \(x \rightarrow 3 \) from the left (\( x \rightarrow 3^-\)) or from the right (\( x \rightarrow 3^+ \)), the magnitude \( |R(x)| \) must approach infinity. This implicates that \( |R(x)| \rightarrow \ \text{infinity} \) as \ x \ approaches \ 3 \.
04
Conclude True or False
Given that \(x=3\) is a vertical asymptote, indeed by definition, \( |R(x)| \rightarrow \ \text{infinity} \) as \ x \ approaches \ 3 \. Therefore, the statement is True.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
rational function
A rational function is a type of function that can be expressed as the ratio of two polynomials. In other words, if you have two polynomial expressions, say, \(P(x)\) and \(Q(x)\), a rational function \(R(x)\) is defined as:
For example, \(R(x) = \frac{2x^2 + 3x - 5}{x^2 - 1}\) is a rational function where:
- \(R(x) = \frac{P(x)}{Q(x)}\)
For example, \(R(x) = \frac{2x^2 + 3x - 5}{x^2 - 1}\) is a rational function where:
- \(P(x) = 2x^2 + 3x - 5\)
- \(Q(x) = x^2 - 1\)
asymptote definition
An asymptote is a line that a graph approaches but never actually touches. There are three main kinds of asymptotes: vertical, horizontal, and oblique. Here, we are focusing on vertical asymptotes.
A vertical asymptote occurs when the function values grow without bound as the input approaches a certain value. For a function \(R(x)\), this usually happens when the denominator \(Q(x)\) becomes zero while the numerator \(P(x)\) is non-zero:
Understanding this helps us see why the given statement is true. A vertical asymptote at \(x = 3\) means as \(x\) gets closer to 3 from either side, \(R(x)\) increases or decreases without limit.
A vertical asymptote occurs when the function values grow without bound as the input approaches a certain value. For a function \(R(x)\), this usually happens when the denominator \(Q(x)\) becomes zero while the numerator \(P(x)\) is non-zero:
- For example, if \(Q(x) = x - 3\), so at \(x = 3\), the function has a vertical asymptote.
Understanding this helps us see why the given statement is true. A vertical asymptote at \(x = 3\) means as \(x\) gets closer to 3 from either side, \(R(x)\) increases or decreases without limit.
limits
Limits are fundamental in calculus and help us understand the behavior of functions at specific points, especially where they may not be defined. The limit of a function \(R(x)\) as \(x\) approaches a specific value \(a\) is written as:
\[ \lim_{{x \to a}} R(x) \]
When dealing with vertical asymptotes, limits tell us how the function behaves as it gets closer to that asymptote. For a vertical asymptote at \(x = 3\), we look at:
In the given exercise, since \( x = 3 \) is a vertical asymptote of \(R(x)\), we conclude that:
\[ \lim_{{x \to a}} R(x) \]
When dealing with vertical asymptotes, limits tell us how the function behaves as it gets closer to that asymptote. For a vertical asymptote at \(x = 3\), we look at:
- \(\lim_{{x \to 3^-}} R(x)\)
- \(\lim_{{x \to 3^+}} R(x)\)
In the given exercise, since \( x = 3 \) is a vertical asymptote of \(R(x)\), we conclude that:
- \(|R(x)| \to \infty\) as \(x \to 3\)