Chapter 7: Problem 108
Explain how you would find the value of \(\sin 390^{\circ}\) using periodic properties.
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 7: Problem 108
Explain how you would find the value of \(\sin 390^{\circ}\) using periodic properties.
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeUse Fundamental Identities and/or the Complementary Angle Theorem to find the exact value of each expression. Do not use a calculator. $$\sin ^{2} 26^{\circ}+\cos ^{2} 26^{\circ}$$
\(f(x)=\sin x, g(x)=\cos x, h(x)=2 x,\) and \(p(x)=\frac{x}{2} .\) Find the value of each of the following: $$ (f-g)\left(60^{\circ}\right) $$
Convert each angle in degrees to radians. Express your answer in decimal form, rounded to two decimal places. \(73^{\circ}\)
Use Fundamental Identities and/or the Complementary Angle Theorem to find the exact value of each expression. Do not use a calculator. $$\frac{\cos 13^{\circ}}{\sin 77^{\circ}}$$
Use a calculator to find the approximate value of each expression. Round the answer to two decimal places. $$ \cos \frac{\pi}{8} $$
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