Chapter 6: Problem 71
Solve each exponential equation. Express irrational solutions in exact form. $$ 4^{x}-10 \cdot 4^{-x}=3 $$
Short Answer
Expert verified
x = \frac{\log(5)}{\log(4)}
Step by step solution
01
- Rewrite the equation using a single base
Given the equation: \[ 4^{x} - 10 \cdot 4^{-x} = 3 \]Rewrite the term involving the negative exponent using a positive exponent: \[ 4^{x} - 10 \cdot \frac{1}{4^{x}} = 3 \]
02
- Substitution
Let \( y = 4^x \). So, \( \frac{1}{y} = 4^{-x} \).Substitute \( y \) into the equation: \[ y - 10 \cdot \frac{1}{y} = 3 \]
03
- Clear the fraction
Multiply both sides by \( y \): \[ y^2 - 10 = 3y \]
04
- Form a quadratic equation
Rearrange the equation into the standard quadratic form: \[ y^2 - 3y - 10 = 0 \]
05
- Solve the quadratic equation
Factor the quadratic equation: \[ (y - 5)(y + 2) = 0 \]So, the solutions are: \[ y = 5 \]\[ y = -2 \]
06
- Back-substitute and find \( x \)
Recall \( y = 4^x \).For \( y = 5 \): \[ 4^x = 5 \]Take the logarithm of both sides: \[ x \cdot \log(4) = \log(5) \]Solve for \( x \): \[ x = \frac{\log(5)}{\log(4)} \]For \( y = -2 \): \[ 4^x = -2 \]There is no real solution since the exponential function cannot be negative.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are essential in mathematics due to their unique properties. An exponential function is defined as \( f(x) = a \times b^x \), where \( a \) and \( b \) are constants, and \( b \) is the base. In these functions, the variable, \( x \), is in the exponent. This allows for rapid growth or decay rates, unlike linear functions which grow at a constant rate.
For example, in the equation \( 4^x - 10 \times 4^{-x} = 3 \), the terms \( 4^x \) and \( 4^{-x} \) are exponential. Measuring quantities like population growth, radioactive decay, and compound interest often use exponential functions.
Understanding the behavior of exponential functions:
For example, in the equation \( 4^x - 10 \times 4^{-x} = 3 \), the terms \( 4^x \) and \( 4^{-x} \) are exponential. Measuring quantities like population growth, radioactive decay, and compound interest often use exponential functions.
Understanding the behavior of exponential functions:
- The larger the base, the steeper the increase or decrease.
- When the exponent is positive, the function depicts growth. A negative exponent describes decay.
- Exponential functions never touch the x-axis; they get infinitely close but do not reach zero.
Quadratic Equations
Solving quadratic equations often plays a crucial role in various mathematical problems. A quadratic equation has the form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are coefficients. In our exercise, after substitution, an exponential equation is transformed into a quadratic equation.
To solve \( y^2 - 3y - 10 = 0 \), follow these steps:
To solve \( y^2 - 3y - 10 = 0 \), follow these steps:
- Factorize the quadratic. In this case, it factors into \( (y - 5)(y + 2) = 0 \). This method works when you can easily identify factors of \( c \) that add up to \( b \).
- Set each factor equal to zero. This gives us \( y - 5 = 0 \) or \( y + 2 = 0 \).
- Solve for \( y \). Hence, we find \( y = 5 \) or \( y = -2 \).
Logarithms
Logarithms are the inverse functions of exponential functions. They help in solving equations where the unknown is in the exponent, making them a powerful tool in various fields. The logarithm of a number is the exponent to which the base must be raised to obtain that number. Specifically, for \( b^x = y \), \( \text{log}_b(y) = x \).
In our exercise, we solve for \( x \) using logarithms. When we have \( 4^x = 5 \), we take the logarithm of both sides:
\( x \times \text{log}(4) = \text{log}(5) \)
Solving for \( x \) gives:
\( x = \frac{\text{log}(5)}{\text{log}(4)} \)
Logarithm properties helpful in solving these equations include:
In our exercise, we solve for \( x \) using logarithms. When we have \( 4^x = 5 \), we take the logarithm of both sides:
\( x \times \text{log}(4) = \text{log}(5) \)
Solving for \( x \) gives:
\( x = \frac{\text{log}(5)}{\text{log}(4)} \)
Logarithm properties helpful in solving these equations include:
- \( \text{log}(ab) = \text{log}(a) + \text{log}(b) \)
- \( \text{log}\frac{a}{b} = \text{log}(a) - \text{log}(b) \)
- \( \text{log}(a^b) = b \times \text{log}(a) \)