Chapter 6: Problem 138
$$ \text { Solve: } \log _{2}\left[\log _{4}\left(\log _{3} x\right)\right]=0 $$
Short Answer
Expert verified
The solution is \( x = 81 \).
Step by step solution
01
Understand the Problem
The given problem is \ \ \log _{2}\left[\log _{4}\left(\log _{3} x\right)\right]=0. Our goal is to find the value of \(x\).
02
Solve the Outer Logarithm
Start by solving the outer logarithm equation \ \ \log _{2}\left[\log _{4}\left(\log _{3} x\right)\right]=0. Since \(\log_{2}(y) = 0\) when \(y = 1\), we get: \ \ \ \log_{4}(\log_{3} x) = 1.
03
Evaluate the Second Logarithm
Next, we solve \(\log_{4}(\log_{3} x) = 1\). Since \(\log_{4}(y) = 1\) when \(y = 4\), we find that: \ \ \log_{3} x = 4.
04
Solve the Inner Logarithm
Now solve for \(x\) in \(\log_{3} x = 4\). This implies: \ \ \ x = 3^{4} = 81.
05
Verify the Solution
Double-check each step to ensure the solution satisfies the original equation. Substituting \(x = 81\), verify: \ \ \ \log_{3}(81) = 4, \ \log_{4}(4) = 1, \ \log_{2}(1) = 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithmic Equations
Logarithmic equations involve unknowns inside logarithms. You solve them by rewriting the equation to isolate the variable or by using logarithmic properties.
To solve \(\text{log}_2\left[\text{log}_4\left(\text{log}_3 x\right)\right] = 0\), we broke it down step by step:
1. Understand that the equation is \(\text{log}_2(\text{some expression}) = 0\).
2. Knowing that a logarithm of 0 represents 1, rewrite the expression as \[\log_4(\log_3(x)) = 1\].
3. Translate the equation into a more straightforward form, one layer at a time.
Another example is solving \(\text{log}_b(y) = c\) by converting it to an exponential form: \(y = b^c\). Using these techniques allows you to manipulate logarithms effectively.
To solve \(\text{log}_2\left[\text{log}_4\left(\text{log}_3 x\right)\right] = 0\), we broke it down step by step:
1. Understand that the equation is \(\text{log}_2(\text{some expression}) = 0\).
2. Knowing that a logarithm of 0 represents 1, rewrite the expression as \[\log_4(\log_3(x)) = 1\].
3. Translate the equation into a more straightforward form, one layer at a time.
Another example is solving \(\text{log}_b(y) = c\) by converting it to an exponential form: \(y = b^c\). Using these techniques allows you to manipulate logarithms effectively.
Logarithmic Properties
Logarithmic properties simplify complex problems and allow solving nested logarithms. Key properties include:
1. **Product Property:** \(\text{log}_b(mn) = \text{log}_b(m) + \text{log}_b(n)\)
2. **Quotient Property:** \(\text{log}_b\left(\frac{m}{n}\right) = \text{log}_b(m) - \text{log}_b(n)\)
3. **Power Property:** \(\text{log}_b(m^p) = p \cdot \text{log}_b(m)\)
4. **Change of Base Formula:** \(\text{log}_b(a) = \frac{\text{log}_k(a)}{\text{log}_k(b)}\)
Identifying and applying these properties can simplify problems significantly. In our exercise, we used the property that \(\text{log}_a(a) = 1\) to convert \(\text{log}_4(4)\) and solve for the inner nested logarithm.
1. **Product Property:** \(\text{log}_b(mn) = \text{log}_b(m) + \text{log}_b(n)\)
2. **Quotient Property:** \(\text{log}_b\left(\frac{m}{n}\right) = \text{log}_b(m) - \text{log}_b(n)\)
3. **Power Property:** \(\text{log}_b(m^p) = p \cdot \text{log}_b(m)\)
4. **Change of Base Formula:** \(\text{log}_b(a) = \frac{\text{log}_k(a)}{\text{log}_k(b)}\)
Identifying and applying these properties can simplify problems significantly. In our exercise, we used the property that \(\text{log}_a(a) = 1\) to convert \(\text{log}_4(4)\) and solve for the inner nested logarithm.
Change of Base Formula
The change of base formula allows converting a logarithm to a different base, making it easier to solve or simplify. The formula is:
\[\text{log}_b(x) = \frac{\text{log}_k(x)}{\text{log}_k(b)}\]
This is particularly useful when dealing with multiple logarithms of different bases.
For example, to solve \(\text{log}_2(16)\), if you are more comfortable with base 10, you can convert it using the change of base formula:
\[\text{log}_2(16) = \frac{\text{log}_{10}(16)}{\text{log}_{10}(2)}\].
Applying this to our nested logarithm problem, while it wasn't directly necessary, knowing how to use the change of base formula equips you with a powerful tool for other logarithmic problems. Practice using this formula alongside basic properties to master logarithmic equations.
\[\text{log}_b(x) = \frac{\text{log}_k(x)}{\text{log}_k(b)}\]
This is particularly useful when dealing with multiple logarithms of different bases.
For example, to solve \(\text{log}_2(16)\), if you are more comfortable with base 10, you can convert it using the change of base formula:
\[\text{log}_2(16) = \frac{\text{log}_{10}(16)}{\text{log}_{10}(2)}\].
Applying this to our nested logarithm problem, while it wasn't directly necessary, knowing how to use the change of base formula equips you with a powerful tool for other logarithmic problems. Practice using this formula alongside basic properties to master logarithmic equations.