Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value, and then find the value. \(f(x)=-2 x^{2}+12 x\)

Short Answer

Expert verified
The function has a maximum value of 18.

Step by step solution

01

Determine the form of the quadratic function

The given quadratic function is \(f(x)=-2 x^{2}+12 x\). It is in the standard form \(f(x)=ax^2 + bx + c\).Here, \(a = -2\), \(b = 12\), and \(c = 0\).
02

Identify the coefficient of the quadratic term

Look at the coefficient of the quadratic term, which is \(a=-2\). Since \(a\) is negative, the parabola opens downwards. This means the function has a maximum value.
03

Find the vertex of the quadratic function

The vertex of a quadratic function \(f(x) = ax^2 + bx + c\) can be found at \(x = -\frac{b}{2a}\). Plug \(a = -2\) and \(b = 12\) into the formula:\[ x = -\frac{12}{2(-2)} = \frac{12}{4} = 3 \]
04

Calculate the value of the function at the vertex

Substitute \(x = 3\) back into the function to find the maximum value:\[ f(3) = -2(3)^2 + 12(3) = -2(9) + 36 = -18 + 36 = 18 \]So, the maximum value of the function is 18.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

vertex formula
In a quadratic function, the vertex is a crucial point where the function reaches its maximum or minimum value. The vertex formula helps us find the x-coordinate of this vertex. For any quadratic function in the standard form: \( f(x) = ax^2 + bx + c \), you can find the x-coordinate of the vertex using the formula:
This formula plays a significant role in analyzing quadratic functions. Plugging the constants from the quadratic equation into this formula directly provides us with the vertex x-coordinate. Knowing this, you can easily determine the function's value at this point to find extremums.
maximum value
In the given quadratic function \( f(x) = -2x^2 + 12x \), we first noted that the coefficient of \(x^2\) is negative (\(a = -2\)). If the leading coefficient \(a\) is negative, the parabola opens downwards, indicating a maximum value at the vertex.
After determining the parabola opens downwards, we've calculated the x-coordinate of the vertex using the vertex formula. By substituting this x-coordinate back into the original function, we determine the maximum function value.
We substituted \(x = 3\) back into the function to get \( f(3) = -2(3)^2 + 12(3) = 18 \), giving us the maximum value of \(18\).
parabola
A quadratic function graph is called a parabola. For the given function \( f(x) = -2x^2 + 12x \), the parabola opens downwards because the coefficient of \(x^2\) (which is \(a\)) is negative. This influences how we determine the vertex and the extremums of the function.
Parabolas have some unique properties:
  • The direction of opening (upwards or downwards) depends on the sign of \(a\).
  • The vertex is the highest or lowest point of the parabola.
  • The axis of symmetry of a parabola is a vertical line that passes through the vertex.

Understanding how the parabola's direction and the vertex's position affect the quadratic function is important. It helps to find the maximum or minimum values without graphing. In summary, recognizing these properties aids in solving and graphing quadratic equations effectively and efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) find the vertex and the axis of symmetry of each quadratic function, and determine whether the graph is concave up or concave down. (b) Find the y-intercept and the \(x\) -intercepts, if any. (c) Use parts (a) and (b) to graph the function. (d) Find the domain and the range of the quadratic function. (e) Determine where the quadratic function is increasing and where it is decreasing. (f) Determine where \(f(x)>0\) and where \(f(x)<0\) \(f(x)=4 x^{2}-2 x+1\)

Let \(R\) represent a company's revenue, let \(C\) represent the company's costs, and let \(x\) represent the number of units produced and sold each day. (a) Find the firm's break-even point; that is, find \(x\) so that \(R=C\) (b) Solve the inequality \(R(x)>C(x)\) to find the units that represent a profit for the company. $$ \begin{array}{l} R(x)=8 x \\ C(x)=4.5 x+17,500 \end{array} $$

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. $$ \text { Graph } x^{2}-4 x+y^{2}+10 y-7=0 $$

Let \(f(x)=a x^{2}+b x+c,\) where \(a, b\) and \(c\) are odd integers. If \(x\) is an integer, show that \(f(x)\) must be an odd integer.

The monthly revenue \(R\) achieved by selling \(x\) wristwatches is \(R(x)=75 x-0.2 x^{2} .\) The monthly cost \(C\) of selling \(x\) wristwatches is $$ C(x)=32 x+1750 $$ (a) How many wristwatches must the firm sell to maximize revenue? What is the maximum revenue? (b) Profit is given as \(P(x)=R(x)-C(x)\). What is the profit function? (c) How many wristwatches must the firm sell to maximize profit? What is the maximum profit? (d) Provide a reasonable explanation as to why the answers found in parts (a) and (c) differ. Explain why a quadratic function is a reasonable model for revenue.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free