Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Explain why the inequality \(x^{2}-x+1<0\) has the empty set as the solution set.

Short Answer

Expert verified
The inequality \(x^2 - x + 1 < 0\) has no solutions because the quadratic function is always positive.

Step by step solution

01

Analyze the quadratic function y = x² - x + 1

Consider the quadratic function given by the expression \(y = x^2 - x + 1\). This inequality requires us to determine where this function is less than zero.
02

Find the discriminant

The discriminant of a quadratic equation \(ax^2 + bx + c = 0\) is given by \(D = b^2 - 4ac\). For our equation \(x^2 - x + 1 = 0\), we have \(a = 1\), \(b = -1\), and \(c = 1\). Therefore, the discriminant is: \[ D = (-1)^2 - 4(1)(1) = 1 - 4 = -3 \]
03

Interpret the discriminant

A negative discriminant (\(D < 0\)) means that the quadratic equation has no real roots, which implies that the quadratic function \(y = x^2 - x + 1\) does not intersect the x-axis. This indicates that the quadratic function is always either above or below the x-axis.
04

Determine the sign of the quadratic function

To determine whether the parabola opens upwards or downwards, look at the coefficient of the \(x^2\) term. Since the coefficient is positive (\(a = 1 > 0\)), the parabola opens upwards. Therefore, \(y = x^2 - x + 1\) is always greater than zero.
05

Conclusion

Since the quadratic function \(y = x^2 - x + 1\) is always greater than zero, there are no values of x for which \(x^2 - x + 1 < 0\). Thus, the solution set is empty.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

discriminant
Understanding the concept of the discriminant is crucial for solving quadratic inequalities. The discriminant is a special value that can be calculated from the coefficients of a quadratic equation.In our case, the quadratic equation was given by y = x^{2}-x + 1. The standard form of a quadratic equation is ax^2 + bx + c = 0, where a, b, and c are the coefficients.The formula to find the discriminant (D) is: b^2 - 4ac.Let's substitute the coefficients from our equation: a = 1, b = -1, and c = 1. Plugging these values into the formula gives D = (-1)^2 - 4(1)(1) = 1 - 4 = -3.The discriminant helps us determine the nature of the roots (solutions) of the equation.In this case, D = -3, which is less than zero. A negative discriminant means that the quadratic equation has no real roots.This also suggests that the graph of the quadratic function does not intersect the x-axis.
quadratic function
A quadratic function is any function that can be written in the form ax^2 + bx + c, where a, b, and c are constants, and x is the variable.Quadratic functions form a parabola when graphed.To understand quadratic functions better, it's helpful to understand their graph.The direction in which the parabola opens is determined by the coefficient a. If a > 0, the parabola opens upwards.If a < 0, the parabola opens downwards.In the case of our function y = x^2 - x + 1, the coefficient a = 1 is positive.So, the parabola opens upwards.Given that we already determined that the discriminant is negative (indicating no real roots), this means our parabola does not touch or cross the x-axis.This tells us something about the inequality x^2 - x + 1 < 0 that we're trying to solve. Since the parabola always lies above the x-axis and opens upwards, our quadratic function y = x^2 - x + 1 is always greater than zero.
solution set
The solution set is where we find the values of x that satisfy the given inequality. For the inequality x^2 - x + 1 < 0, we need values where the quadratic function is less than zero. However, from the analysis of the quadratic function and its discriminant, we see that this particular function y = x^2 - x + 1 is always positive for all real numbers.That means there are no values of x for which the quadratic function becomes less than zero.So the inequality x^2 - x + 1 < 0 has no solutions in the real number system.Therefore, the solution set is empty.Understanding the solution set of quadratic inequalities is essential in identifying where a function's values lie relative to a given threshold—especially in advanced mathematical problems like optimization and modeling.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Why is the graph of a quadratic function concave up if \(a>0\) and concave down if \(a<0 ?\)

The distance \(d\) between the bottom of a suspended spring and a countertop is a linear function of the weight \(w\) attached to the bottom of the spring. The bottom of the spring is 9 inches from the countertop whenthe attached weight is 1.5 pounds and 5 inches from the countertop when the attached weight is 2.5 pounds. (a) Find a linear model that relates the distance \(d\) from the countertop and the weight \(w\). (b) Find the distance between the bottom of the spring and the countertop if no weight is attached. (c) What is the smallest weight that will make the bottom of the spring reach the countertop? (Ignore the thickness of the weight.)

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Find the \(x\) -intercept \((\mathrm{s})\) and \(y\) -intercepts(s) of the graph of \(4 x^{2}+9 y=72\)

The graph of the function \(f(x)=a x^{2}+b x+c\) has vertex at (1,4) and passes through the point \((-1,-8) .\) Find \(a, b\), and \(c\)

Revenue The John Deere company has found that the revenue from sales of heavy- duty tractors is a function of the unit price \(p,\) in dollars, that it charges. The revenue \(R,\) in dollars, is given by $$ R(p)=-\frac{1}{2} p^{2}+1900 p $$ (a) At what prices \(p\) is revenue zero? (b) For what range of prices will revenue exceed \(\$ 1,200,000 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free