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Determine whether each function is linear or nonlinear. If it is linear, determine the slope. $$ \begin{array}{|rc|} \hline \boldsymbol{x} & \boldsymbol{y}=\boldsymbol{f}(\boldsymbol{x}) \\ \hline-2 & 4 \\ -1 & 1 \\ 0 & -2 \\ 1 & -5 \\ 2 & -8 \\ \hline \end{array} $$

Short Answer

Expert verified
The function is linear with a slope of -3.

Step by step solution

01

- Understand the Problem

The given function is represented by a set of points. Determine whether it is linear or nonlinear and then find the slope if it is linear.
02

- Check for Linearity

To check if the function is linear, determine if the rate of change between each consecutive pair of points is constant. Calculate the rate of change (slope) using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
03

- Calculate Slopes

Calculate the slopes between consecutive points: \[ m_{1} = \frac{1 - 4}{-1 - (-2)} = \frac{-3}{1} = -3 \] \[ m_{2} = \frac{-2 - 1}{0 - (-1)} = \frac{-3}{1} = -3 \] \[ m_{3} = \frac{-5 - (-2)}{1 - 0} = \frac{-3}{1} = -3 \] \[ m_{4} = \frac{-8 - (-5)}{2 - 1} = \frac{-3}{1} = -3 \]
04

- Analyze

Since the slope between each pair of consecutive points is the same, the function is linear.
05

- State the Result

The function is linear with a constant slope of \( -3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Determine Linearity
Determining if a function is linear or non-linear is essential. A function is linear if its rate of change (or slope) remains consistent between all its points. Linear functions graph to a straight line, while non-linear functions do not.

To determine linearity: - Calculate the slopes (or rates of change) between each consecutive set of points using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1} \) - Check if these slopes are equal.

In the provided solution, the function was confirmed linear as every calculated slope was 'm'= -3. If the slope varied, the function would be non-linear.

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Most popular questions from this chapter

Use the fact that a quadratic function of the form \(f(x)=a x^{2}+b x+c\) with \(b^{2}-4 a c>0\) may also be written in the form \(f(x)=a\left(x-r_{1}\right)\left(x-r_{2}\right),\) where \(r_{1}\) and \(r_{2}\) are the \(x\) -intercepts of the graph of the quadratic function. (a) Find quadratic functions whose \(x\) -intercepts are -3 and 1 with \(a=1 ; a=2 ; a=-2 ; a=5\) (b) How does the value of \(a\) affect the intercepts? (c) How does the value of \(a\) affect the axis of symmetry? (d) How does the value of \(a\) affect the vertex? (e) Compare the \(x\) -coordinate of the vertex with the midpoint of the \(x\) -intercepts. What might you conclude?

(a) find the vertex and the axis of symmetry of each quadratic function, and determine whether the graph is concave up or concave down. (b) Find the y-intercept and the \(x\) -intercepts, if any. (c) Use parts (a) and (b) to graph the function. (d) Find the domain and the range of the quadratic function. (e) Determine where the quadratic function is increasing and where it is decreasing. (f) Determine where \(f(x)>0\) and where \(f(x)<0\) \(f(x)=4 x^{2}-2 x+1\)

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. $$ \text { Graph } x^{2}-4 x+y^{2}+10 y-7=0 $$

Can a quadratic function have a range of \((-\infty, \infty)\) ? Justify your answer.

The graph of the function \(f(x)=a x^{2}+b x+c\) has vertex at (1,4) and passes through the point \((-1,-8) .\) Find \(a, b\), and \(c\)

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