Chapter 4: Problem 19
In Problems \(7-22,\) solve each inequality. \(19.4 x^{2}+9<6 x\)
Short Answer
Expert verified
The inequality has no real solutions.
Step by step solution
01
- Move all terms to one side
Begin by moving all terms to one side of the inequality to set it to zero. Subtract \(6x\) from both sides: \[19.4 x^{2} + 9 - 6x < 0.\]
02
- Reorder the terms
Reorder the terms in the standard quadratic form \(ax^2 + bx + c < 0\): \[19.4 x^{2} - 6x + 9 < 0.\]
03
- Find the roots of the equation
To find the critical points, solve the corresponding equation for equality: \[19.4 x^{2} - 6x + 9 = 0.\] Use the quadratic formula: \[x = \frac{{-b \, \text{±} \, \sqrt{{b^2 - 4ac}}}}{{2a}},\] where \(a = 19.4, b = -6, c = 9\).
04
- Calculate the discriminant
Compute the discriminant \(\text{{Δ}}\): \[Δ = b^2 - 4ac = (-6)^2 - 4(19.4)(9) = 36 - 696 = -660.\] Since the discriminant is negative, there are no real roots.
05
- Analyze the quadratic expression
Since there are no real roots and the coefficient \(a = 19.4\) is positive, the quadratic expression \(19.4 x^{2} - 6x + 9\) is always positive for all real values of \x\. Thus, the inequality \[19.4 x^{2} - 6x + 9 < 0\] has no real solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool to solve quadratic equations of the form \(ax^2 + bx + c = 0\). This formula can be expressed as: \[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}.\] To use it, you need the coefficients \(a\), \(b\), and \(c\) from your quadratic equation. Simply plug them into the formula to find the solutions or roots of the equation.
- The term \(b^2 - 4ac\) under the square root is called the discriminant.
- The \(\pm \) symbol means you will get two results: one with addition and one with subtraction.
Discriminant
The discriminant (denoted as \(\Delta\)) is an important part of the quadratic formula. It's found inside the square root: \[\Delta = b^2 - 4ac.\] The value of the discriminant tells us about the nature of the roots:
- If \(\Delta > 0\), there are two distinct real roots.
- If \(\Delta = 0\), there is exactly one real root (the roots are repeated).
- If \(\Delta < 0\), there are no real roots (the roots are complex numbers).
No Real Roots
When the discriminant is negative, the quadratic equation has no real roots. This means the graph of the quadratic function does not intersect the x-axis. For our inequality \19.4x^2 - 6x + 9 < 0\, since \(\Delta = -660 \) (a negative value), we concluded that there are no real roots.
Additionally:
Additionally:
- Because the coefficient of \(x^2\) (which is \(a = 19.4\)) is positive, the parabola opens upwards.
- This tells us that the quadratic expression \19.4x^2 - 6x + 9\ is always positive for all real values of \(x\).