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$$\text { If } g(x)=\frac{2}{3} x-8, \text { find } g\left(\frac{3}{2} x+12\right)$$

Short Answer

Expert verified
g\left(\frac{3}{2}x + 12\right) = x

Step by step solution

01

- Substitute the Inner Function

Identify the inner function to be substituted into the main function \(g(x)\). Here, the inner function is \(\frac{3}{2}x + 12\). Substitute this into \(g(x)\) to get \(g\left(\frac{3}{2}x + 12\right)\).
02

- Apply the Main Function

Use the definition of \(g(x) = \frac{2}{3}x - 8\). Replace \(x\) in the definition with the inner function: \(g\left(\frac{3}{2}x + 12\right) = \frac{2}{3}\left(\frac{3}{2}x + 12\right) - 8\).
03

- Simplify the Expression

Distribute \(\frac{2}{3}\) through the inner function: \(\frac{2}{3} \left(\frac{3}{2}x + 12\right) = \frac{2}{3} \cdot \frac{3}{2}x + \frac{2}{3} \cdot 12\). This simplifies to \(x + 8\). So, \(g\left(\frac{3}{2}x + 12\right) = x + 8 - 8\).
04

- Final Simplification

Combine like terms in the expression: \(x + 8 - 8\). The constants \(+ 8\) and \(- 8\) cancel out, leaving \(x\). Therefore, \(g\left(\frac{3}{2}x + 12\right) = x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inner Function
In function composition, the inner function is the function that you first substitute into another function. Think of it as a 'function within a function.' In the exercise, we need to find what happens when you input \(\frac{3}{2}x+12\) into \(g(x)\).

Here, \(g(x) = \frac{2}{3} x - 8\), and our inner function is \(\frac{3}{2}x + 12\). We start by plugging this inner function into \(g(x)\).

So, this step essentially involves identifying which part needs to be substituted into the main function.
Substitution
Substitution is a key concept in function composition. When working with the inner function, you replace the variable in the outer function with the inner function's expression.

In our exercise, we take the inner function \(\frac{3}{2}x + 12\) and substitute it into \(g(x)\). Essentially, wherever we see an \(x\) in \(g(x)\), we replace it with \(\frac{3}{2}x + 12\).

  • Original function: \(g(x) = \frac{2}{3} x - 8\)
  • Substitute inner function: \(g\bigg(\frac{3}{2}x+12\bigg)=\frac{2}{3}\bigg(\frac{3}{2}x + 12\bigg) - 8\)
Distribution
Distribution involves multiplying each term inside a parenthesis by a term outside the parenthesis. In simple terms, it is about spreading out the multiplication across the terms within the parenthesis.

In our step-by-step solution, we distribute \( \frac{2}{3} \) to both \( \frac{3}{2}x \) and \(12\):

\[\frac{2}{3} \bigg(\frac{3}{2} x + 12\bigg) = \bigg(\frac{2}{3} \times \frac{3}{2}\bigg)x + \bigg(\frac{2}{3} \times 12\bigg) = x + 8 \]

After this step, the expression simplifies, allowing us to move closer to the final result.
Simplification
Simplification is about combining like terms to make an equation or expression easier to read or solve. In our exercise, after distributing, we combine \(+8\bigg)\) and \(-8\):

\[\bigg(x + 8 - 8 \bigg) = x\]

In simplification, always look for opportunities to combine like terms or eliminate terms that cancel each other out. This process makes the equation much simpler and reveals the final answer more clearly:

Thus, \(g\bigg(\frac{3}{2}x + 12\bigg) = x\).

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Most popular questions from this chapter

Make up a quadratic function that opens down and has only one \(x\) -intercept. Compare yours with others in the class. What are the similarities? What are the differences?

(a) find the vertex and the axis of symmetry of each quadratic function, and determine whether the graph is concave up or concave down. (b) Find the y-intercept and the \(x\) -intercepts, if any. (c) Use parts (a) and (b) to graph the function. (d) Find the domain and the range of the quadratic function. (e) Determine where the quadratic function is increasing and where it is decreasing. (f) Determine where \(f(x)>0\) and where \(f(x)<0\) \(f(x)=3 x^{2}+6 x+2\)

(a) find the vertex and the axis of symmetry of each quadratic function, and determine whether the graph is concave up or concave down. (b) Find the y-intercept and the \(x\) -intercepts, if any. (c) Use parts (a) and (b) to graph the function. (d) Find the domain and the range of the quadratic function. (e) Determine where the quadratic function is increasing and where it is decreasing. (f) Determine where \(f(x)>0\) and where \(f(x)<0\) \(f(x)=x^{2}-2 x-3\)

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. $$ \text { Graph } g(x)=\left\\{\begin{array}{cl} x^{2} & \text { if } x \leq 0 \\ \sqrt{x}+1 & \text { if } x>0 \end{array}\right. $$

Use the fact that a quadratic function of the form \(f(x)=a x^{2}+b x+c\) with \(b^{2}-4 a c>0\) may also be written in the form \(f(x)=a\left(x-r_{1}\right)\left(x-r_{2}\right),\) where \(r_{1}\) and \(r_{2}\) are the \(x\) -intercepts of the graph of the quadratic function. (a) Find quadratic functions whose \(x\) -intercepts are -3 and 1 with \(a=1 ; a=2 ; a=-2 ; a=5\) (b) How does the value of \(a\) affect the intercepts? (c) How does the value of \(a\) affect the axis of symmetry? (d) How does the value of \(a\) affect the vertex? (e) Compare the \(x\) -coordinate of the vertex with the midpoint of the \(x\) -intercepts. What might you conclude?

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