Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine whether the equation defines y as a function of \(x .\) \(y=|x|\)

Short Answer

Expert verified
Yes, \(y = |x|\) defines \(y\) as a function of \(x\).

Step by step solution

01

Identify the given equation

The given equation is \(y = |x|\). This equation involves the absolute value of \(x\).
02

Understand the definition of a function

A function is a relation in which each input (\(x\)) has a unique output (\(y\)). In other words, for every value of \(x\), there should be exactly one corresponding \(y\).
03

Analyze the absolute value function

The absolute value of \(x\), denoted \(|x|\), is always a non-negative value. It means that \(|x| = x\) if \(x \geq 0\) and \(|x| = -x\) if \(x < 0\).
04

Evaluate the uniqueness of outputs for each input

For any given \(x\), \(|x|\) will always produce a single value. For example, if \(x = 3\), \(|3| = 3\). If \(x = -3\), \(|-3| = 3\).
05

Conclusion

Since the absolute value function \(y = |x|\) produces a unique value for every input \(x\), the equation defines \(y\) as a function of \(x\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relation and Function
Let's start by understanding what a function is. In mathematics, a function is a way of matching elements from one set (called the domain) to elements in another set (called the range). A relation is any pairing of elements from one set to another. Functions are special types of relations where each input has exactly one output. This means if you have an equation like \(y = |x|\), each value you plug in for \(x|\) gives you only one specific value for \(y|\). This unique pairing is what makes an equation a function. It ensures that there are no ambiguities or multiple outcomes for any given input.
Unique Output
Now let's go deeper into the idea of a unique output. When we say that a function provides a unique output for each input, we're essentially stating the distinctiveness rule of functions. Consider the equation \(y = |x|\). If you input \(x = 2\), the absolute value is \(2\), and \(y\) will also be \(2\). If you input \(x = -2\), the absolute value is still \(2\), hence \(y\) will again be \(2|\). No matter what value you choose for \(x|\), \(y|\) always ends up being a single, specific number, thereby providing a unique output. This confirms that our equation \(y = |x|\) behaves as a function since it assigns one and only one value to \(y|\) for every \(x|\).
Non-Negative Value
One interesting feature of the absolute value function is that it always produces non-negative values. The absolute value of a number is its distance from zero on the number line, regardless of direction. For the function \(y = |x|\), whether \(x\) is positive, negative, or zero, \(y\) will always be either positive or zero. This is because the absolute value converts negative inputs to positive outputs. If \(x\) is positive or zero, \(y\) simply equals \(x\). If \(x\) is negative, \(y\) equals the positive counterpart of \(x\). For example: \(y = |-3| \) becomes \(y = 3\). No input will ever yield a negative value for \(y|\). This non-negative property is a key component in identifying the nature of absolute value functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

$$ F(x)=-x^{4}+8 x^{2}+9 $$ (a) Determine whether \(F\) is even, odd, or neither. (b) There is a local maximum value of 25 at \(x=2 .\) Find a second local maximum value. (c) Suppose the area of the region enclosed by the graph of \(F\) and the \(x\) -axis between \(x=0\) and \(x=3\) is 50.4 square units. Using the result from (a), determine the area of the region enclosed by the graph of \(F\) and the \(x\) -axis between \(x=-3\) and \(x=0\).

The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. Problems \(85-92\) require the following discussion of a secant line. The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. \(f(x)=x^{2}+2 x\)

Find the slope of a line perpendicular to the line $$ 3 x-10 y=12 $$

Solve for \(D\) if $$ 3 y^{2} \cdot D+3 x^{2}-3 x y^{2}-3 x^{2} y \cdot D=0 $$

For the function \(f(x)=x^{2},\) compute the average rate of change: \(\begin{array}{ll}\text { (a) From } 1 \text { to } 2 & \text { (b) From } 1 \text { to } 1.5\end{array}\) (c) From 1 to 1.1 (d) From 1 to 1.01 (e) From 1 to 1.001 (f) Use a graphing utility to graph each of the secant lines along with \(f\) (g) What do you think is happening to the secant lines? (h) What is happening to the slopes of the secant lines? Is there some number that they are getting closer to? What is that number?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free