Chapter 2: Problem 84
The solar electric generating systems at Kramer Junction, California, use parabolic troughs to heat a heat-transfer fluid to a high temperature. This fluid is used to generate steam that drives a power conversion system to produce electricity. For troughs 7.5 feet wide, an equation for the cross section is \(16 y^{2}=120 x-225\). (a) Find the intercepts of the graph of the equation. (b) Test for symmetry with respect to the \(x\) -axis, the \(y\) -axis, and the origin.
Short Answer
Step by step solution
- Rewrite the equation
- Find x-intercept
- Find y-intercept
- Test for symmetry with respect to the x-axis
- Test for symmetry with respect to the y-axis
- Test for symmetry with respect to the origin
- Summarize findings
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intercepts
- **X-intercept:** Found by setting \(y = 0\) in the equation and solving for \(x\).
- **Y-intercept:** Found by setting \(x = 0\) in the equation and solving for \(y\).
For the given equation, \[16 y^{2} = 120 x - 225\], let's derive the intercepts:
*X-Intercept*:
Setting \(y = 0\), we get:
\[0 = \frac{120x - 225}{16}\]
This simplifies to:
\[120x = 225\]
So, the x-intercept is \( \frac{15}{8}\).
*Y-Intercept*:
Setting \(x = 0\), we get:
\[y^{2} = \frac{-225}{16} = -\frac{225}{16}\]
Since \(y^{2}\) cannot be negative, there is no y-intercept.
Symmetry
- **X-axis Symmetry:** Replace \(y\) with \(-y\) and check if the equation remains unchanged.
- **Y-axis Symmetry:** Replace \(x\) with \(-x\) and check if the equation remains unchanged.
- **Origin Symmetry:** Replace \(x\) with \(-x\) and \(y\) with \(-y\), then check if the equation stays the same.
For the given equation \[16 y^{2} = 120x - 225\]:
*X-axis Symmetry:*
Replace \(y\) with \(-y\):
\[16(-y)^{2} = 120x - 225\]
Since \[16 y^{2} = 120x - 225\], the graph is symmetric about the x-axis.
*Y-axis Symmetry:*
Replace \(x\) with \(-x\):
\[16 y^{2} = 120(-x) - 225\]
\[16 y^{2} = -120x - 225\] is not the original equation, so no y-axis symmetry.
*Origin Symmetry:*
Replace \(x\) with \(-x\) and \(y\) with \(-y\):
\[16(-y)^{2} = 120(-x) - 225\]
\[16 y^{2} = -120x - 225\] is not the original equation, so no symmetry with respect to the origin.
Parabolic Equations
A common form is \[y = ax^{2} + bx + c\], but other forms like \[Ax^{2} + Bxy + Cy^{2} + Dx + Ey + F = 0\] also exist.
For the given problem, the equation \[16 y^{2} = 120 x - 225\] represents a horizontal parabola opening rightwards. Here's why:
- The equation is rewritten as \[y^{2} = \frac{120x - 225}{16}\] showing \(y^{2}\) in terms of \(x\), typical for parabolas that open horizontally.
- If \(y^{2}\) is isolated, positive \(x\) shifts the vertex to the right, indicating the opening direction.
Coordinate Geometry
Key concepts include:
- **Distance Formula:** Measures the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) given by \[ \text{Distance} = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}\]
- **Midpoint Formula:** Finds the midpoint of a line segment joining \((x_1, y_1)\) and \((x_2, y_2)\) given by \[ \text{Midpoint} = \left( \frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2} \right) \]
Using coordinate geometry helps dissect the problem effectively:
* The distance from the vertex to the focus in a parabola highlights its shape.
* Midpoints help identify central points in symmetrical objects.
Combining these principles allows deeper insight into the parabolic equations and their respective graphs.