Chapter 2: Problem 59
Solve each equation. \(7-3|4 x-7|=4\)
Short Answer
Expert verified
Solutions are \(x = \frac{31}{12}\) and \(x = \frac{11}{12}\).
Step by step solution
01
Isolate the Absolute Value
First, add 3 to both sides of the equation to isolate the absolute value term: \(7 - 3|4x - 7| + 3 = 4 + 3\) which simplifies to \(10 = 3|4x - 7|\)
02
Divide Both Sides
Next, divide both sides by 3: \(\frac{10}{3} = |4x - 7|\)
03
Set Up Two Equations
Set up two separate equations to account for the positive and negative solutions to the absolute value equation: \(4x - 7 = \frac{10}{3}\) and \(4x - 7 = -\frac{10}{3}\)
04
Solve the First Equation
Solve for \(x\) in the first equation: \(4x - 7 = \frac{10}{3}\)Add 7 to both sides: \(4x = \frac{10}{3} + 7 = \frac{10}{3} + \frac{21}{3} = \frac{31}{3}\)Divide by 4: \(x = \frac{31}{3} \times \frac{1}{4} = \frac{31}{12}\)
05
Solve the Second Equation
Solve for \(x\) in the second equation: \(4x - 7 = -\frac{10}{3}\)Add 7 to both sides: \(4x = -\frac{10}{3} + 7 = -\frac{10}{3} + \frac{21}{3} = \frac{11}{3}\)Divide by 4: \(x = \frac{11}{3} \times \frac{1}{4} = \frac{11}{12}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
solving absolute value equations
Solving absolute value equations can seem tricky at first, but once you understand the steps, it becomes much simpler. To start, recall that the absolute value of a number is its distance from zero, regardless of direction. This means an absolute value equation will have two possible solutions: one positive and one negative. In other words, when you solve for the variable, you need to consider both positive and negative outcomes.
If you're given an equation like \(7-3|4 x-7|=4\), your goal is to 'free' the absolute value expression so you can handle it more easily. Just follow the methodical steps of isolating the absolute value and setting up separate equations for the positive and negative scenarios. Each step brings you closer to the final solution.
Whether you’re dealing with linear equations, inequalities, or real-world scenarios, mastering absolute value equations will always come in handy.
If you're given an equation like \(7-3|4 x-7|=4\), your goal is to 'free' the absolute value expression so you can handle it more easily. Just follow the methodical steps of isolating the absolute value and setting up separate equations for the positive and negative scenarios. Each step brings you closer to the final solution.
Whether you’re dealing with linear equations, inequalities, or real-world scenarios, mastering absolute value equations will always come in handy.
isolating absolute value
The first critical step to solving any absolute value equation is isolating the absolute value expression. Think of it like peeling away layers to get to the core of the problem. Start by moving all other terms to one side of the equation.
Looking at the exercise \(7-3|4 x-7|=4\), our first goal is to get the absolute value term \(|4x - 7|\) by itself. To do this:
Looking at the exercise \(7-3|4 x-7|=4\), our first goal is to get the absolute value term \(|4x - 7|\) by itself. To do this:
- Add 3 to both sides:
- \(7 - 3|4x - 7| + 3 = 4 + 3\)
- Which simplifies to:
- \(10 = 3|4x - 7|\)
- Divide both sides by 3:
- \(\frac{10}{3} = |4x - 7|\)
positive and negative solutions
When solving absolute value equations, remember that for any absolute value expression |A|, it equals A or -A. After isolating the absolute value term, you set up two equations: one where the expression inside the absolute value equals the positive right-hand side, and another where it equals the negative.
From our isolated equation \(\frac{10}{3} = |4x - 7|\), we write two new equations:
From our isolated equation \(\frac{10}{3} = |4x - 7|\), we write two new equations:
- \(4x - 7 = \frac{10}{3}\)
- \(4x - 7 = -\frac{10}{3}\)
- \4x - 7 = \frac{10}{3}\
- Add 7: \4x = \frac{10}{3} + 7 = \frac{10}{3} + \frac{21}{3} = \frac{31}{3}\
- Divide by 4: \x = \frac{31}{12}\
- \4x - 7 = -\frac{10}{3}\
- Add 7: \4x = -\frac{10}{3} + 7 = -\frac{10}{3} + \frac{21}{3} = \frac{11}{3}\
- Divide by 4: \x = \frac{11}{12}\