Chapter 2: Problem 12
write a general formula to describe each variation. \(T\) varies directly with the cube root of \(x\) and the square of \(d ;\) \(T=18\) when \(x=8\) and \(d=3\)
Short Answer
Expert verified
\(T = \sqrt[3]{x} \times d^2\)
Step by step solution
01
Understand the direct variation formula
Given that a quantity varies directly with other quantities, we use the formula: \[ T = k \times (\text{other quantities}) \] where\( k \)is a constant. In this case, we have T varies directly with the cube root of x and the square of d.
02
Write the direct variation formula
Since T varies directly with \ \ \( \sqrt[3]{x}\) and \(d^2\), we write the formula: \[ T = k \times \sqrt[3]{x} \times d^2 \]
03
Substitute the given values to find k
We are given that \( T = 18\) when \( x = 8\) and \(d = 3\). Substitute these values into the equation: \[ 18 = k \times \sqrt[3]{8} \times 3^2 \]
04
Calculate the cube root and square
First, calculate \( \sqrt[3]{8} \): \[ \sqrt[3]{8} = 2 \] Then calculate \(3^2 \): \[ 3^2 = 9 \]
05
Solve for k
Substitute these values back into the equation \[ 18 = k \times 2 \times 9 \] Simplify and solve for \( k \): \[ 18 = 18k \] \[ k = 1 \]
06
Write the general formula
Now that we know \( k = 1\), we can write the general formula for T: \[ T = \sqrt[3]{x} \times d^2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Direct Variation
In mathematics, direct variation describes a relationship where one quantity directly depends on another. This means if one quantity increases, the other does as well, and vice versa. The formula for direct variation is generally written as:
\[ T = k \times (\text{other quantities}) \]
here,\( k \)is a constant known as the constant of variation. In our exercise, \( T \)varies directly with the cube root of \( x \)and the square of \( d \). Therefore, the direct variation formula becomes:
\[ T = k \times \sqrt[3]{x} \times d^2 \]
This means that the value of \( T \)is proportional to the product of the cube root of \( x \)and the square of \( d \). To find the specific relationship, we need to determine the value of \( k \), which will make the formula match given conditions.
\[ T = k \times (\text{other quantities}) \]
here,\( k \)is a constant known as the constant of variation. In our exercise, \( T \)varies directly with the cube root of \( x \)and the square of \( d \). Therefore, the direct variation formula becomes:
\[ T = k \times \sqrt[3]{x} \times d^2 \]
This means that the value of \( T \)is proportional to the product of the cube root of \( x \)and the square of \( d \). To find the specific relationship, we need to determine the value of \( k \), which will make the formula match given conditions.
Calculating Cube Roots
Finding the cube root of a number means finding a value that, when multiplied by itself three times, gives the original number. For example, to find the cube root of 8, we ask:
The answer is 2, because \( 2 \times 2 \times 2 = 8 \). Therefore, \( \sqrt[3]{8} = 2 \). Understanding cube roots is essential in problems involving direct variation where one of the variables is a cube root. For example, in our equation, if \( x = 8 \), then \( \sqrt[3]{8} = 2 \). This simplifies our calculations when applying the direct variation formula.
- What number multiplied by itself three times equals 8?
The answer is 2, because \( 2 \times 2 \times 2 = 8 \). Therefore, \( \sqrt[3]{8} = 2 \). Understanding cube roots is essential in problems involving direct variation where one of the variables is a cube root. For example, in our equation, if \( x = 8 \), then \( \sqrt[3]{8} = 2 \). This simplifies our calculations when applying the direct variation formula.
Working with Squares
The square of a number involves multiplying the number by itself. It answers the question:
Squaring is straightforward but crucial in problems dealing with direct variation where a variable is squared. In the given task, \( d \)is squared in the formula. So, if \( d = 3 \), then \( d^2 = 9 \). Plugging these simplified values into the variation formula allows for easy computation.
In the exercise, substituting the given values and simplifying:
\[ T = k \times \sqrt[3]{8} \times 3^2 \]which becomes \[ T = k \times 2 \times 9 \] helps us find \( k \), the constant of variation, and thus write the final direct variation formula.
- What do you get when you multiply a number by itself?
Squaring is straightforward but crucial in problems dealing with direct variation where a variable is squared. In the given task, \( d \)is squared in the formula. So, if \( d = 3 \), then \( d^2 = 9 \). Plugging these simplified values into the variation formula allows for easy computation.
In the exercise, substituting the given values and simplifying:
\[ T = k \times \sqrt[3]{8} \times 3^2 \]which becomes \[ T = k \times 2 \times 9 \] helps us find \( k \), the constant of variation, and thus write the final direct variation formula.