Chapter 14: Problem 10
Find the value of each permutation. $$ P(8,8) $$
Short Answer
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Step by step solution
01
Understand the Permutation Formula
The formula for permutations of selecting k items from n distinct items is given by \[ P(n, k) = \frac{n!}{(n-k)!} \] where \( n! \) represents the factorial of n.
02
Substitute the Values
In this problem, both n and k are 8. Substitute these values into the formula: \[ P(8, 8) = \frac{8!}{(8-8)!} = \frac{8!}{0!} \]
03
Simplify the Factorial Expressions
Recall that \( 0! = 1 \). Therefore, the expression simplifies as: \[ P(8, 8) = \frac{8!}{1} \]
04
Calculate 8!
Calculate the factorial of 8: \[ 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40320 \]
05
Final Result
Thus, substituting back, we get: \[ P(8, 8) = 40320 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorial Calculations
Factorials are crucial in permutations. The factorial of a number, denoted as \( n! \), is the product of all positive integers up to that number. For example, \[ 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40320 \].
Factorials grow very fast. \[ 5! = 120 \], but \[ 10! = 3628800 \], a huge leap.
Here are some key points about factorials:
Understanding how to calculate and use factorials is essential for solving permutation problems.
Factorials grow very fast. \[ 5! = 120 \], but \[ 10! = 3628800 \], a huge leap.
Here are some key points about factorials:
- \[ 0! \] is defined to be 1.
- The factorial function is only defined for non-negative integers.
- They are widely used in combinatorics, permutations, and combinations.
Understanding how to calculate and use factorials is essential for solving permutation problems.
Permutation Formula
Permutations consider the arrangement of a set of items. When dealing with permutations, we calculate the number of ways to arrange k items out of n distinct items.
The generic formula for permutations is: \[ P(n, k) = \frac{n!}{(n-k)!} \]
Here: \[ n \] is the total number of items.
\[ k \] is the number of items we are arranging.
For example, in the exercise: \[ P(8, 8) \] uses both \[ n \] and \[ k \] as 8. Substituting into the formula: \[ P(8, 8) = \frac{8!}{(8-8)!} = \frac{8!}{0!} = 40320 \]
Permutations are essential in many probability and combinatorics problems, where the order of selection matters.
The generic formula for permutations is: \[ P(n, k) = \frac{n!}{(n-k)!} \]
Here: \[ n \] is the total number of items.
\[ k \] is the number of items we are arranging.
For example, in the exercise: \[ P(8, 8) \] uses both \[ n \] and \[ k \] as 8. Substituting into the formula: \[ P(8, 8) = \frac{8!}{(8-8)!} = \frac{8!}{0!} = 40320 \]
Permutations are essential in many probability and combinatorics problems, where the order of selection matters.
Combinatorics
Combinatorics is a broader field of mathematics focused on counting, arrangement, and combination of objects. It plays a crucial role in statistics, computer science, and many other fields.
Here's a quick snapshot:
Combinatorics helps in solving complex problems by breaking them into manageable counting exercises.
Mastering these concepts can boost your problem-solving skills and understanding of how different arrangements and selections work!
Here's a quick snapshot:
- **Permutations**: Counts the number of ways to arrange a set of items where the order matters. For example, how many different ways to arrange 3 books on a shelf.
- **Combinations**: Deals with selecting items from a set where the order does not matter. For instance, choosing 3 fruits out of a basket of 5 different fruits.
- **Factorials**: Utilized heavily in permutations and combinations to calculate arrangements and selections efficiently.
Combinatorics helps in solving complex problems by breaking them into manageable counting exercises.
Mastering these concepts can boost your problem-solving skills and understanding of how different arrangements and selections work!