Chapter 13: Problem 82
Trout Population A pond currently contains 2000 trout. A fish hatchery decides to add 20 trout each month. It is also known that the trout population is growing at a rate of \(3 \%\) per month. The size of the population after \(n\) months is given by the recursively defined sequence \(p_{0}=2000 \quad p_{n}=1.03 p_{n-1}+20\)
Short Answer
Step by step solution
Understand the Problem
Identify Initial Value
Understand Recursive Formula
Calculate Population for First Month
Calculate Population for Second Month
Calculate Population for Third Month
Generalize the Formula
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Recursive Sequences
\( p_0 = 2000 \)
\( p_n = 1.03 p_{n-1} + 20 \)
- **\( p_{n-1} \)** represents the population from the previous month- The term **1.03** accounts for 3% growth- An additional **20** trout is added each month.
Exponential Growth
- When the initial population is 2000, a 3% increase is 60 trout.
- When the population becomes 2060, the 3% increase is approximately 61.8 trout.
Initial Value Problem
- Start by identifying the initial population: \( p_0 = 2000 \).
- Use the recursive formula to find the population for the first month: \( p_1 = 1.03 \times 2000 + 20 = 2060 \).
- Apply the formula iteratively for each subsequent month using the newly calculated population as the new previous term.
Population Modeling
- Determining the initial population size.
- Identifying relevant growth rates and additional factors (like hatchery additions).
- Constructing a formula to predict future populations based on previous data.