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The given pattern continues. Write down the nth term of a sequence \(\left\\{a_{n}\right\\}\) suggested by the pattern. \(\frac{1}{1 \cdot 2}, \frac{1}{2 \cdot 3}, \frac{1}{3 \cdot 4}, \frac{1}{4 \cdot 5}, \ldots\)

Short Answer

Expert verified
The nth term is \(a_{n} = \frac{1}{n \times (n+1)}\).

Step by step solution

01

- Observe the Pattern

Examine the initial terms to identify the pattern: \(\frac{1}{1 \times 2}, \frac{1}{2 \times 3}, \frac{1}{3 \times 4}, \frac{1}{4 \times 5}, \rightarrow \frac{1}{n \times (n+1)}\).
02

- Generalize the Formula

From the observations, note that each term can be written in the form \(\frac{1}{n \times (n+1)}\), where \(n\) starts from 1 and increases by 1 for each subsequent term.
03

- Write the nth Term

Based on the pattern observed, the nth term of the sequence is: \(a_{n} = \frac{1}{n \times (n+1)}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequences and Series
In mathematics, a sequence is an ordered list of numbers. Each number in a sequence is called a term. For example, in the sequence given in the exercise - \(\frac{1}{1 \times 2}, \frac{1}{2 \times 3}, \frac{1}{3 \times 4}, \frac{1}{4 \times 5}, \) - each fraction represents a term.
A series, on the other hand, is the sum of the terms of a sequence. In this case, we are only dealing with a sequence, not a series.
Understanding the difference between the two is important. A sequence lists numbers in a specific order, while a series adds them up.
Pattern Recognition
The ability to recognize patterns is crucial in solving problems involving sequences. In this exercise, we are tasked with identifying how each term in the sequence relates to its position (n).
Start by examining the initial terms:
  • First term: \(\frac{1}{1 \times 2}\)
  • Second term: \(\frac{1}{2 \times 3}\)
  • Third term: \(\frac{1}{3 \times 4}\)
  • And so on.
Notice that the denominator in each term can be written as \(n \times (n+1)\). Recognizing this consistent pattern is key to formulating the nth term.
General Term Formula
Once we have identified the pattern, the next step is to generalize the formula for the nth term. From our observation:
  • For n=1, the term is \(\frac{1}{1 \times 2}\)
  • For n=2, the term is \(\frac{1}{2 \times 3}\)
  • For n=3, the term is \(\frac{1}{3 \times 4}\)
We see that each term follows a specific rule: the numerator is always 1, and the denominator is the product of n and \(n+1\). Hence, we can write the nth term as:
\[a_{n} = \frac{1}{n \times (n+1)}\]
Algebraic Sequences
An algebraic sequence is a sequence where each term is derived using a specific algebraic formula. Algebraic sequences often have a clear pattern and mathematical relationship between the terms.
In our given exercise, the sequence \(\frac{1}{1 \times 2}, \frac{1}{2 \times 3}, \frac{1}{3 \times 4}, \frac{1}{4 \times 5}, \) is an excellent example of an algebraic sequence. Here, each term is expressed as an algebraic fraction.
Recognizing algebraic sequences and understanding their formulas can simplify the process of finding any term within the sequence. It transforms complex ideas into manageable calculations and allows for general understanding beyond just memorizing terms.

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Most popular questions from this chapter

A special section in the end zone of a football stadium has 2 seats in the first row and 14 rows total. Each successive row has 2 seats more than the row before. In this particular section, the first seat is sold for 1 cent, and each following seat sells for \(5 \%\) more than the previous seat. Find the total revenue generated if every seat in the section is sold. Round only the final answer, and state the final answer in dollars rounded to two decimal places. (JJC) \(^{\dagger}\)

Bode's Law In \(1772,\) Johann Bode published the following formula for predicting the mean distances, in astronomical units (AU), of the planets from the sun: $$ a_{1}=0.4 \quad a_{n}=0.4+0.3 \cdot 2^{n-2} $$ where \(n \geq 2\) is the number of the planet from the sun. (a) Determine the first eight terms of the sequence. (b) At the time of Bode's publication, the known planets were Mercury \((0.39 \mathrm{AU}),\) Venus \((0.72 \mathrm{AU}),\) Earth \((1 \mathrm{AU})\) Mars \((1.52 \mathrm{AU}),\) Jupiter \((5.20 \mathrm{AU}),\) and Saturn \((9.54 \mathrm{AU})\) How do the actual distances compare to the terms of the sequence? (c) The planet Uranus was discovered in \(1781,\) and the asteroid Ceres was discovered in \(1801 .\) The mean orbital distances from the sun to Uranus and Ceres " are \(19.2 \mathrm{AU}\) and \(2.77 \mathrm{AU},\) respectively. How well do these values fit within the sequence? (d) Determine the ninth and tenth terms of Bode's sequence. (e) The planets Neptune and Pluto" were discovered in 1846 and \(1930,\) respectively. Their mean orbital distances from the sun are \(30.07 \mathrm{AU}\) and \(39.44 \mathrm{AU},\) respectively. How do these actual distances compare to the terms of the sequence? (f) On July \(29,2005,\) NASA announced the discovery of a dwarf planet \((n=11),\) which has been named Eris. Use Bode's Law to predict the mean orbital distance of Eris from the sun. Its actual mean distance is not yet known, but Eris is currently about 97 astronomical units from the sun.

Use the Principle of Mathematical Induction to show that the given statement is true for all natural numbers \(n\). $$ 4+3+2+\cdots+(5-n)=\frac{1}{2} n(9-n) $$

Determine whether the given sequence is arithmetic, geometric, or neither. If the sequence is arithmetic, find the common difference; if it is geometric, find the common ratio. If the sequence is arithmetic or geometric, find the sum of the first 50 terms. $$ -1,2,-4,8, \ldots $$

Determine whether the given sequence is arithmetic, geometric, or neither. If the sequence is arithmetic, find the common difference; if it is geometric, find the common ratio. If the sequence is arithmetic or geometric, find the sum of the first 50 terms. $$ \left\\{\left(\frac{5}{4}\right)^{n}\right\\} $$

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