Chapter 13: Problem 10
Show that each sequence is arithmetic. Find the common difference, and list the first four terms. $$ \left\\{b_{n}\right\\}=\\{3 n+1\\} $$
Short Answer
Expert verified
The sequence is arithmetic with a common difference of 3 and the first four terms are 4, 7, 10, and 13.
Step by step solution
01
- Determine the General Form
The given sequence is defined by the general term \( b_n = 3n + 1 \).
02
- Calculate the First Term
To find the first term, substitute n = 1 into the general term: \( b_1 = 3(1) + 1 = 4 \).
03
- Calculate the Second Term
Substitute n = 2 into the general term to get the second term: \( b_2 = 3(2) + 1 = 7 \).
04
- Calculate the Third Term
Substitute n = 3 into the general term to get the third term: \( b_3 = 3(3) + 1 = 10 \).
05
- Calculate the Fourth Term
Substitute n = 4 into the general term to get the fourth term: \( b_4 = 3(4) + 1 = 13 \).
06
- Verify the Common Difference
To check if the sequence is arithmetic, find the difference between consecutive terms: \( b_2 - b_1 = 7 - 4 = 3 \), \( b_3 - b_2 = 10 - 7 = 3 \), and \( b_4 - b_3 = 13 - 10 = 3 \). The common difference d is 3, confirming that the sequence is arithmetic.
07
- Summarize the Findings
The sequence \( \{b_n\} = 3n + 1 \) is arithmetic with a common difference of 3. The first four terms are 4, 7, 10, and 13.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Difference
In an arithmetic sequence, the 'common difference' is a key element that separates an arithmetic sequence from other types of sequences. It is the constant difference between consecutive terms in the sequence.
Finding the common difference involves a simple subtraction:
you subtract the first term from the second term, the second term from the third, and so forth.
For our sequence defined by \( b_n = 3n + 1 \), we can calculate the common difference by subtracting:
This means our common difference, denoted as \(d\), is 3.
The value of \(d\) is crucial in proving whether a sequence is arithmetic. If the difference remains constant throughout, the sequence is indeed an arithmetic sequence.
Finding the common difference involves a simple subtraction:
you subtract the first term from the second term, the second term from the third, and so forth.
For our sequence defined by \( b_n = 3n + 1 \), we can calculate the common difference by subtracting:
- \( b_2 - b_1 = 7 - 4 = 3 \)
- \( b_3 - b_2 = 10 - 7 = 3 \)
- \( b_4 - b_3 = 13 - 10 = 3 \)
This means our common difference, denoted as \(d\), is 3.
The value of \(d\) is crucial in proving whether a sequence is arithmetic. If the difference remains constant throughout, the sequence is indeed an arithmetic sequence.
General Term
The general term of an arithmetic sequence provides a formula to find any term in the sequence. It is often expressed in the form
\[ b_n = a + (n-1)d \]
where:
\( b_n = 3n + 1 \)
Here, compare it with the standard form, we identify:
\( a = 4 \) (calculated as the first term when \( n = 1 \))
\( d = 3 \) (our common difference).
Having a general term allows us to find the value of any term in the sequence without having to manually calculate each previous term. For instance, if we need to find the 10th term, we just substitute \( n = 10 \) into the general term formula:
\[ b_{10} = 3*10 + 1 = 30 + 1 = 31 \]
\[ b_n = a + (n-1)d \]
where:
- \(a\) is the first term
- \(d\) is the common difference
- \(n\) is the term number (or position in the sequence)
\( b_n = 3n + 1 \)
Here, compare it with the standard form, we identify:
\( a = 4 \) (calculated as the first term when \( n = 1 \))
\( d = 3 \) (our common difference).
Having a general term allows us to find the value of any term in the sequence without having to manually calculate each previous term. For instance, if we need to find the 10th term, we just substitute \( n = 10 \) into the general term formula:
\[ b_{10} = 3*10 + 1 = 30 + 1 = 31 \]
Sequence Verification
Verifying whether a sequence is arithmetic involves checking the common difference throughout the sequence. If the common difference is constant, the sequence is arithmetic.
In our exercise, we already calculated the first few terms using:
\( b_1 = 3(1) + 1 = 4 \)
\( b_2 = 3(2) + 1 = 7 \)
\( b_3 = 3(3) + 1 = 10 \)
\( b_4 = 3(4) + 1 = 13 \)
Next, we checked the differences between consecutive terms:
In our exercise, we already calculated the first few terms using:
\( b_1 = 3(1) + 1 = 4 \)
\( b_2 = 3(2) + 1 = 7 \)
\( b_3 = 3(3) + 1 = 10 \)
\( b_4 = 3(4) + 1 = 13 \)
Next, we checked the differences between consecutive terms:
- \( b_2 - b_1 = 7 - 4 = 3 \)
- \( b_3 - b_2 = 10 - 7 = 3 \)
- \( b_4 - b_3 = 13 - 10 = 3 \)
First Four Terms
Listing the first four terms of an arithmetic sequence helps in verifying its properties and better understanding its structure.
Given the sequence defined by \( b_n = 3n + 1 \), we use this formula to get the first four terms by substituting \( n\) values from 1 to 4:
Given the sequence defined by \( b_n = 3n + 1 \), we use this formula to get the first four terms by substituting \( n\) values from 1 to 4:
- First term: \( b_1 = 3(1) + 1 = 4 \)
- Second term: \( b_2 = 3(2) + 1 = 7 \)
- Third term: \( b_3 = 3(3) + 1 = 10 \)
- Fourth term: \( b_4 = 3(4) + 1 = 13 \)