Chapter 12: Problem 41
Solve each system of equations using Cramer's Rule if is applicable. If Cramer's Rule is not applicable, write, "Not applicable". \(\left\\{\begin{array}{r}x-2 y+3 z=0 \\ 3 x+y-2 z=0 \\ 2 x-4 y+6 z=0\end{array}\right.\)
Short Answer
Expert verified
Not applicable
Step by step solution
01
Determine the coefficient matrix (A)
Identify the coefficients of the variables from each equation to form matrix A.\[ A = \begin{pmatrix} 1 & -2 & 3 \ 3 & 1 & -2 \ 2 & -4 & 6 \end{pmatrix} \]
02
Compute the determinant of the coefficient matrix (det(A))
To check if Cramer's Rule is applicable, calculate the determinant of matrix A.\[ \text{det}(A) = \begin{vmatrix} 1 & -2 & 3 \ 3 & 1 & -2 \ 2 & -4 & 6 \end{vmatrix} \]Expanding along the first row,\[ \text{det}(A) = 1 \cdot \begin{vmatrix} 1 & -2 \ -4 & 6 \end{vmatrix} - (-2) \cdot \begin{vmatrix} 3 & -2 \ 2 & 6 \end{vmatrix} + 3 \cdot \begin{vmatrix} 3 & 1 \ 2 & -4 \end{vmatrix} \]Calculating the sub-determinants,\[ \begin{vmatrix} 1 & -2 \ -4 & 6 \end{vmatrix} = (1)(6) - (-2)(-4) = 6 - 8 = -2 \]\[ \begin{vmatrix} 3 & -2 \ 2 & 6 \end{vmatrix} = (3)(6) - (-2)(2) = 18 + 4 = 22 \]\[ \begin{vmatrix} 3 & 1 \ 2 & -4 \end{vmatrix} = (3)(-4) - (1)(2) = -12 - 2 = -14 \]Substitute back into the determinant equation,\[ \text{det}(A) = 1 \cdot (-2) - (-2) \cdot 22 + 3 \cdot (-14) \= -2 + 44 - 42 = 0 \]
03
Analyze the determinant
Since \( \text{det}(A) = 0\), the coefficient matrix A is singular, meaning it does not have an inverse. Therefore, Cramer's Rule is not applicable in this case.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant of a Matrix
In the world of linear algebra, the **determinant** is a special number that can be calculated from a square matrix. It provides important properties about the matrix and the system of linear equations it represents. Given a matrix A, the determinant is denoted as \( \text{det}(A) \) or sometimes just |A|.
The determinant is calculated through a specific arithmetic process. For a 3x3 matrix like the one in the original exercise, the calculation involves decomposing the matrix into smaller 2x2 determinants (sub-determinants). Each sub-determinant is found by removing one row and one column and then applying the rule: \( ad - bc \).
Therefore, if you have a 3x3 matrix:
The determinant is calculated through a specific arithmetic process. For a 3x3 matrix like the one in the original exercise, the calculation involves decomposing the matrix into smaller 2x2 determinants (sub-determinants). Each sub-determinant is found by removing one row and one column and then applying the rule: \( ad - bc \).
Therefore, if you have a 3x3 matrix:
- Expand along any row or column
- Compute the sub-determinants
- Add and subtract them accordingly
System of Linear Equations
A **system of linear equations** is a collection of one or more linear equations involving the same set of variables. For example, in the original exercise:
There are three possible outcomes when solving such systems:
- \( x - 2y + 3z = 0 \)
- \( 3x + y - 2z = 0 \)
- \( 2x - 4y + 6z = 0 \)
There are three possible outcomes when solving such systems:
- **Unique Solution:** One specific set of values solves all equations (this happens when the determinant of the coefficient matrix is non-zero).
- **No Solution:** No sets of values satisfy all equations (usually happens when the equations represent parallel lines).
- **Infinitely Many Solutions:** There are multiple (or infinite) sets of values that can solve the equations (this often occurs when the determinant is zero, indicating dependent equations).
Singular Matrix
A **singular matrix** is a square matrix that does not have an inverse. This is indicated by its determinant being zero (\( \text{det}(A) = 0 \)).
When dealing with systems of linear equations, a singular matrix means that the system either has no solution or infinitely many solutions, but not a unique solution. This is the conclusion we reached in the original exercise when we found that \( \text{det}(A) = 0 \).
Some key points to remember about singular matrices:
When dealing with systems of linear equations, a singular matrix means that the system either has no solution or infinitely many solutions, but not a unique solution. This is the conclusion we reached in the original exercise when we found that \( \text{det}(A) = 0 \).
Some key points to remember about singular matrices:
- They cannot be inverted.
- They indicate linear dependence within the rows or columns, meaning some rows or columns are just multiples of others.
- In the context of solving linear equations, they tell us that Cramer's Rule is not applicable.