Chapter 10: Problem 69
Graph each pair of polar equations on the same polar grid. Find the polar coordinates of the point(s) of intersection and label the point(s) on the graph. $$ r=\sin \theta ; r=1+\cos \theta $$
Short Answer
Expert verified
The points of intersection are (\( \frac{\sqrt2}{2} , \ \frac{\pi}{4} \)) and (\( \frac{\sqrt2}{2} , \ \frac{7\pi}{4} \)).
Step by step solution
01
Understand the Polar Equations
The given polar equations are: 1. \(r = \sin \theta\) 2. \(r = 1 + \cos \theta\)
02
Graph the Equations
Plot each equation on the same polar grid. The equation \(r = \sin \theta\) represents a circle passing through the origin, centered at \((0, \frac{1}{2})\). The equation \(r = 1 + \cos \theta\) represents a cardioid.
03
Set the Equations Equal to Find Intersection
To find the points of intersection, set \( \sin \theta = 1 + \cos \theta \).
04
Isolate \( \theta \)
Rearrange the equation to \( \sin \theta - \cos \theta = 1 \). Use trigonometric identities to simplify further. \( \sin \theta = 1 + \cos \theta \) Using identities: \( \sin \theta - \cos \theta = 1 \) Divide by \sqrt2: \( \frac{\sin \theta - \cos \theta}{\sqrt2} = \frac{1}{\sqrt2} \) That simplifies to \( \sin(\theta - \frac{\pi}{4})= \frac{1}{\sqrt2} \). So, \( \theta = \frac{\pi}{4} + 2n\pi\) or \( \theta = \frac{7\pi}{4} + 2n\pi\).
05
Find r for Intersection Points
For \( \theta = \frac{\pi}{4}\): \( r = \sin \frac{\pi}{4} = \frac{\sqrt2}{2} \). For \( \theta = \frac{7\pi}{4} \): \( r = \sin \frac{7\pi}{4} = \frac{-\sqrt2}{2} \). So, \( r = \sqrt2 \frac{1+\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}} \). Thus, points are: (\( \frac{\sqrt2}{2} , \ \frac{\pi}{4} \) and \( \frac{\sqrt2}{2} , \ \frac{7\pi}{4} \)
06
Label Points on the Graph
Plot and label the intersection points found in Step 5: ( \( \frac{\sqrt2}{2}, \ \frac{\pi}{4} \) and \( \frac{\sqrt2}{2}, \ \frac{7\pi}{4} \)). These points should be marked clearly on the polar grid.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates offer a different way to describe the position of points compared to the Cartesian coordinate system. Instead of using \( (x, y) \) pairs, polar coordinates \( (r, \theta) \) consist of:
- \( r \): the radius or distance from the origin.
- \( \theta \): the angle from the positive x-axis, measured in radians.
Graphing Polar Equations
To graph polar equations, it’s essential to understand the shape each equation represents. Let’s consider the equations provided:
\(r = \sin \theta \): This is a circle that passes through the origin and is centered at \( (0, \frac{1}{2}) \). As \( \theta \) increases from 0 to 2\( \pi \), the value of \( r \) changes accordingly, sketching out the circle.
\(r = 1 + \cos \theta \): This represents a cardioid, a heart-shaped curve that touches the origin. It occurs because, at \( \theta = \pi \), \( r = 0 \).
To graph these, plot several points for varying \( \theta \) values and connect them smoothly. Using polar grid paper can help visualize and plot these shapes accurately. Practice plotting these will bolster confidence in working with different polar equations.
\(r = \sin \theta \): This is a circle that passes through the origin and is centered at \( (0, \frac{1}{2}) \). As \( \theta \) increases from 0 to 2\( \pi \), the value of \( r \) changes accordingly, sketching out the circle.
\(r = 1 + \cos \theta \): This represents a cardioid, a heart-shaped curve that touches the origin. It occurs because, at \( \theta = \pi \), \( r = 0 \).
To graph these, plot several points for varying \( \theta \) values and connect them smoothly. Using polar grid paper can help visualize and plot these shapes accurately. Practice plotting these will bolster confidence in working with different polar equations.
Intersection Points
Finding intersection points in polar equations requires setting the equations equal to each other and solving for \( \theta \). For this exercise:
- Equate \( \sin \theta \) to \(1 + \cos \theta \).
- Simplify to find the common angles: \( \sin \theta - \cos \theta = 1 \).
- Use trigonometric identities to solve further. You get: \( \sin( \theta - \frac{ \pi }{4} ) = \frac {1}{ \sqrt{2} } \).
- Solve this to find \( \theta = \frac{ \pi }{ 4 } \) and \( \frac {7 \pi } {4 } \).
- \( \frac{ \sqrt{ 2 } }{2}, \frac { \pi } {4 } \)
- \( \frac{ormalsize \sqrt{ 2 } } {2}, \frac{ 7 \pi } { 4 } \)