Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Solve: \(3^{2 x-3}=9^{1-x}\)

Short Answer

Expert verified
x = \frac{5}{4}

Step by step solution

01

Rewrite the Equation with the Same Base

Start by expressing both sides of the equation with the same base. Note that 9 can be written as a power of 3, specifically, 9 = 3^2. So, rewrite the equation: \[3^{2x-3} = (3^2)^{1-x}\]
02

Simplify the Right Side Using Exponent Rules

Apply the exponent rule \((a^m)^n = a^{mn}\) to simplify the right-hand side: \[3^{2x-3} = 3^{2(1-x)}\]
03

Set the Exponents Equal to Each Other

Since the bases are the same, set the exponents equal to each other: \[2x - 3 = 2(1 - x)\]
04

Solve the Exponential Equation

Expand the right-hand side and solve for x: \[2x - 3 = 2 - 2x\]Add 2x to both sides: \[2x + 2x - 3 = 2\]Simplify: \[4x - 3 = 2\]Add 3 to both sides: \[4x = 5\]Divide by 4: \[x = \frac{5}{4}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rewrite Equations with Same Base
When solving exponential equations, it's often useful to rewrite each term with the same base. This makes it easier to compare and solve.
For instance, in the problem given, we start with:
\(3^{2x-3}=9^{1-x}\).
Notice that 9 is a power of 3. Remember that 9 is equal to 3 squared, i.e., \(9 = 3^2\).
Rewriting the equation using this same base helps immensely.
The rewritten equation looks like this:
\(3^{2x-3} = (3^2)^{1-x}\).
Now, both sides of the equation have the same base.
Exponent Rules
Exponent rules are essential tools when working with exponential equations. They offer a way to simplify expressions and solve equations more easily.
Some key exponent rules include:
  • Product Rule: \(a^m \cdot a^n = a^{m+n}\)
  • Quotient Rule: \(\frac{a^m}{a^n} = a^{m-n}\)
  • Power of a Power Rule: \((a^m)^n = a^{mn}\)
  • Zero Exponent Rule: \(a^0 = 1\) where a ≠ 0

In our problem, we used the Power of a Power Rule. Specifically, we simplified: \( (3^2)^{1-x} = 3^{2(1-x)}\).
This rule helps convert the nested exponents into a single exponent for easier comparison. Now our equation looks like: \(3^{2x-3} = 3^{2(1-x)}\).
Solving Exponential Equations
After rewriting the equation with the same base and applying exponent rules, we need to solve for the variable.
Here’s the simplified equation: \3^{2x-3} = 3^{2(1-x)}\
Since both sides have the same base, we can set their exponents equal to each other:
\2x - 3 = 2(1 - x)\
Now, solve for x:
Expand the right-hand side: \2x - 3 = 2 - 2x\.
Add \2x\ to both sides: \2x + 2x - 3 = 2\.
Simplify: \4x - 3 = 2\.
Add 3 to both sides: \4x = 5\.
Finally, divide by 4: \x = \frac{5}{4}\.
So, the solution to the exponential equation is \(x = \frac{5}{4}\).
With practice, these steps become second nature, and solving similar problems gets easier.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An Airbus A 320 jet maintains a constant airspeed of \(500 \mathrm{mph}\) headed due west. The jet stream is \(100 \mathrm{mph}\) in the southeasterly direction. (a) Express the velocity \(\mathbf{v}_{\text {a }}\) of the A320 relative to the air and the velocity \(\mathbf{v}_{\mathrm{w}}\) of the jet stream in terms of i and \(\mathbf{j}\). (b) Find the velocity of the \(\mathrm{A} 320\) relative to the ground. (c) Find the actual speed and direction of the \(\mathrm{A} 320\) relative to the ground.

The letters \(x\) and \(y\) represent rectangular coordinates. Write each equation using polar coordinates \((r, \theta) .\) $$ x^{2}+y^{2}=x $$

Solar Energy The amount of energy collected by a solar panel depends on the intensity of the sun's rays and the area of the panel. Let the vector I represent the intensity, in watts per square centimeter, having the direction of the sun's rays. Let the vector \(\mathbf{A}\) represent the area, in square centimeters, whose direction is the orientation of a solar panel. See the figure. The total number of watts collected by the panel is given by \(W=|\mathbf{I} \cdot \mathbf{A}|\) Suppose that \(\mathbf{I}=\langle-0.02,-0.01\rangle\) and \(\mathbf{A}=\langle 300,400\rangle\) (a) Find \(\|\mathbf{I}\|\) and \(\|\mathbf{A}\|,\) and interpret the meaning of each. (b) Compute \(W\) and interpret its meaning. (c) If the solar panel is to collect the maximum number of watts, what must be true about I and \(\mathbf{A}\) ?

Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Solve: \(7^{x-1}=3 \cdot 2^{x+4}\)

Given vectors \(\mathbf{u}=2 x \mathbf{i}+3 \mathbf{j}\) and \(\mathbf{v}=x \mathbf{i}-8 \mathbf{j},\) find \(x\) so that \(\mathbf{u}\) and \(\mathbf{v}\) are orthogonal.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free