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Find the real solutions, if any, of each equation. $$ 3 x^{2}+7 x-20=0 $$

Short Answer

Expert verified
The real solutions are \( x = \frac{5}{3} \) and \( x = -4 \).

Step by step solution

01

Identify the coefficients

In the quadratic equation, identify the coefficients, where the equation is in the form of \(ax^2 + bx + c = 0\). Here, \(a = 3\), \(b = 7\), and \(c = -20\).
02

Apply the quadratic formula

Use the quadratic formula to find the solutions of the equation: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute \(a = 3\), \(b = 7\), and \(c = -20\) into the formula.
03

Calculate the discriminant

Compute the discriminant, \(D = b^2 - 4ac\). Here, \( D = 7^2 - 4 \cdot 3 \cdot (-20)\), thus, \(D = 49 + 240 = 289\).
04

Calculate the solutions

Since the discriminant is positive, there are real solutions. Use the quadratic formula to find these: \(x = \frac{-7 \pm \sqrt{289}}{6}\), hence, \(x = \frac{-7 \pm 17}{6}\). This gives two solutions: \(x_1 = \frac{-7 + 17}{6} = \frac{10}{6} = \frac{5}{3}\), and \(x_2 = \frac{-7 - 17}{6} = \frac{-24}{6} = -4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

quadratic formula
When you're solving quadratic equations, one of the most reliable tools you can use is the quadratic formula. The formula is written as:

  • First, identify the coefficients from your quadratic equation. These coefficients are typically denoted as 'a', 'b', and 'c'.
    In our example, we have the equation:






  • Once you've identified 'a', 'b', and 'c', you can plug them into the quadratic formula:




  • Finally, simplify the results to find the solutions to the quadratic equation.
    For our example, after plugging in the coefficients, we would continue to simplify until we find the values of 'x' that satisfy the equation.





coefficients
Understanding coefficients is crucial when working with quadratic equations. Coefficients are the numerical factors in front of the variables in an equation. In a standard form quadratic equation, which looks like this:

  • 'a' is the coefficient of the term with squared variable, which in our example is 3.

  • 'b' is the coefficient of the term with the single variable, which is 7.

  • 'c' is the constant term, in this case, -20.



Each of these coefficients plays a role in the quadratic formula. Accurately identifying and substituting them into the formula can greatly simplify the problem-solving process. For our given equation:





Remember:

  • Consistency in identifying 'a', 'b', and 'c'.


  • Correctly substituting them into the quadratic formula.

  • Carefully performing the arithmetic operations.
discriminant
The discriminant, represented by 'D', is a key part of the quadratic formula. The discriminant helps determine the nature of the roots of the quadratic equation. The formula for the discriminant is:

  • In our example, where 'b' is 7, 'a' is 3, and 'c' is -20, the discriminant is calculated as follows:



  • The value of the discriminant is 289.



The value of the discriminant tells us:
  • If 'D' is positive, the quadratic equation has two distinct real roots.
  • If 'D' is zero, there is exactly one real root.
  • If 'D' is negative, there are no real roots; instead, there are two complex roots.

In our solved example, the discriminant is 289, a positive value, indicating two distinct real roots. Sure enough, when we solved the equation, we got:





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Most popular questions from this chapter

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If \(k=\frac{x+3}{x-4}\) and \(k^{2}-3 k=28,\) find \(x\)

Find all the real solutions of \(12 x^{7 / 5}+3 x^{2 / 5}=13 x^{9 / 10}\).

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The distance to the surface of the water in a well can sometimes be found by dropping an object into the well and measuring the time elapsed until a sound is heard. If \(t_{1}\) is the time (measured in seconds) that it takes for the object to strike the water, then \(t_{1}\) will obey the equation \(s=16 t_{1}^{2}\), where \(s\) is the distance (measured in feet). It follows that \(t_{1}=\frac{\sqrt{s}}{4}\). Suppose that \(t_{2}\) is the time that it takes for the sound of the impact to reach your ears. Because sound waves are known to travel at a speed of approximately 1100 feet per second, the time \(t_{2}\) to travel the distance \(s\) will be \(t_{2}=\frac{s}{1100} .\) See the illustration. Now \(t_{1}+t_{2}\) is the total time that elapses from the moment that the object is dropped to the moment that a sound is heard. We have the equation $$ \text { Total time elapsed }=\frac{\sqrt{s}}{4}+\frac{s}{1100} $$ Find the distance to the water's surface if the total time elapsed from dropping a rock to hearing it hit water is 4 seconds.

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