Chapter 0: Problem 85
Perform the indicated operations and simplify the result. Leave your answer in factored form. $$ \frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2} $$
Short Answer
Expert verified
The simplified form is \( \frac{3x - 1}{2x + 1} \).
Step by step solution
01
Understand the problem
Identify the expression given: \( \frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2} \). Notice that \( (x-1)^{-1} = \frac{1}{x-1} \). Replace \( (x-1)^{-1} \) with \( \frac{1}{x-1} \) in the expression.
02
Replace the negative exponents
Rewrite the expression: \( \frac{2 \frac{1}{x-1} + 3}{3 \frac{1}{x-1} + 2} \).
03
Combine terms with common denominators
Factor out \( \frac{1}{x-1} \) from the numerator and denominator: \( \frac{\frac{2 + 3(x-1)}{x-1}}{\frac{3 + 2(x-1)}{x-1}} \).
04
Simplify the simplified fractions
Simplify the numerators and denominators separately: \( \frac{2 + 3(x-1)}{3 + 2(x-1)} \).
05
Distribute and simplify
Distribute the constants: \( \frac{2 + 3x - 3}{3 + 2x - 2} = \frac{3x - 1}{2x + 1} \).
06
Factor, if possible
Check if the expression can be factored further. In this case, \( \frac{3x - 1}{2x + 1} \) is already in its simplest form.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring
Factoring is an important concept in algebra that involves breaking down an expression into simpler components, called factors, that can be multiplied together to obtain the original expression. By factoring, complex expressions become easier to manipulate and solve. In this exercise, however, the final expression \(\frac{3x - 1}{2x + 1}\) could not be factored further. Let's understand the process:
- Factor polynomials wherever possible
- Explore common factors in the numerator and denominator
- Ensure the expression is in its simplest form
Fractions
Dealing with fractions involves understanding and working with the numerator (top part) and the denominator (bottom part) of a fraction. In algebra, fractions often have variables in them too. Here's how we managed the fractions in this exercise:
- Recognize the role of the numerator and denominator in algebraic fractions
- Combine fractions with common denominators
- Simplify complex fractions by manipulating their terms
Negative Exponents
Negative exponents can seem tricky at first, but they're quite straightforward once you get the hang of them. A term with a negative exponent, such as \(a^{-n}\), can be rewritten as \frac{1}{a^n}\. In the given exercise, we replaced \((x-1)^{-1}\) with \frac{1}{x-1}\:
- Understand the notation of negative exponents
- Convert negative exponents into fractions
- Simplify expressions by combining similar terms
Rational Expressions
Rational expressions are fractions where the numerator and the denominator are both polynomials. Simplifying these requires various algebraic techniques including factoring, finding common denominators, and canceling common factors. Here’s the approach we used for rational expressions in this exercise:
- Identify the polynomials in the numerator and denominator
- Factor out common terms
- Combine like terms and simplify the expression
Algebraic Manipulation
Algebraic manipulation refers to the techniques used for rewriting algebraic expressions in different forms. This involves a variety of methods such as combining like terms, factoring, expanding, and simplifying fractions. Here's what was done in this exercise:
- Replace negative exponents with fractions
- Factor and combine terms with common denominators
- Simplify the final expression by distributing and combining terms