Question

Find the amplitude if it exists and period of the function $y=3\sin \left(\theta \right)$ and then graph the function.

Short answer

The amplitude of $y=3\sin \left(\theta \right)$is $3$.

The period of $y=3\sin \left(\theta \right)$ is $2\pi$.

Step-by-step solution

Step 1. Write down the given information.

The given function is $y=3\sin \left(\theta \right)$.

Step 2. Concept used.

A function of the form $y=a\sin \left(bx\right)\text{and}y=a\cos \left(bx\right)$has amplitude of $a$and period $\frac{360°}{\left|b\right|}\text{or}\frac{2\pi }{\left|b\right|}$.

Step 3. Evaluating amplitude and period of the given function.

With the help of concept stated above, the amplitude and period of the function is evaluated as:

The amplitude of $y=3\sin \left(\theta \right)$is $\left|3\right|=3$.

The period of $y=3\sin \left(\theta \right)$ is $\frac{2\pi }{\left|1\right|}=2\pi$.

Step 4. Sketch the graph for the function.

The graph for the function $y=3\sin \left(\theta \right)$ is shown below.

Step 5. Conclusion.

The amplitude of $y=3\sin \left(\theta \right)$is $3$.

The period of $y=3\sin \left(\theta \right)$ is $2\pi$.