Question

$\frac{1}{4}(p-7)=\frac{1}{3}(p+5)$

Short answer

The value of$p=-41$

Step-by-step solution

- The given information

$\frac{1}{4}(p-7)=\frac{1}{3}(p+5)$

Step 2

$$\begin{gathered} \frac{1}{4}(p-7)=\frac{1}{3}(p+5) \\ \Rightarrow \frac{p}{4}-\frac{7}{4}=\frac{p}{3}+\frac{5}{3} \\ \Rightarrow \frac{p}{4}-\frac{p}{3}=\frac{5}{3}+\frac{7}{4} \\ \Rightarrow \frac{3p-4p}{12}=\frac{20+21}{12} \\ \Rightarrow -\frac{p}{12}=\frac{41}{12} \\ \Rightarrow p=-41 \end{gathered}$$