Chapter 1: Q63. (page 46)
set on a number line.Solve each inequality. Describe the solution set using set builder or interval notation. Then graph the solution
63.
Short Answer
Solution set of inequality is .
Solution set on number line is
Chapter 1: Q63. (page 46)
set on a number line.Solve each inequality. Describe the solution set using set builder or interval notation. Then graph the solution
63.
Solution set of inequality is .
Solution set on number line is
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Get started for freeIn 1950, the average price of a car was about . This may sound inexpensive, but the average income in 1950 was much less than it is now. To compare dollar amounts over time, use the formula , where A is the old dollar amount, S is the starting year’s Consumer price index (CPI), C is the converting year’s CPI, and V is the current value of the old dollar amount. Buying a car for in 1950 was like buying a car for how much money in 2000?
Year | Average CPI |
1950 | 42.1 |
1960 | 29.6 |
1970 | 38.8 |
1980 | 82.4 |
1990 | 130.7 |
2000 | 174.0 |
Identify the additive inverse and multiplicative inverse for each number
11.
Identify the additive inverse and multiplicative inverse for each number
10.
Find the value of each expression
Evaluate each expression if and
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