Question

Evaluate each expression $x=4,y=-2,$if and $z=6$

$x+\left[3\left(y+z\right)-y\right]$

Short answer

Expression$x+\left[3\left(y+z\right)-y\right]$ results into 18.

Step-by-step solution

- Order of simplification

To evaluate any expression involving more than one operation, follow the below order of operations:

• First evaluate expressions inside grouping symbols like parentheses ( ) or brackets [ ].
• Evaluate the exponents.
• Perform Multiplication and division from left to right.
• Perform addition and subtraction from left to right.

- Substitute given values

Simplify parentheses by adding$y$with $z$. Then multiply result with 3 and subtract y from it.

Finally add resultant with $x$.

Substitute 4 for $x$,$-2$for$y$and 6 for $z$ into given expression

$x+\left[3\left(y+z\right)-y\right]=4+\left[3\left(\left(-2\right)+6\right)-\left(-2\right)\right]$

- Simplify 4+3-2+6--2

Follow order of simplification

$\left(-2\right)+6=4$

Then

$3\left(4\right)=12$

Then

$12-\left(-2\right)=14$

Finally

localid="1645014756558" $4+14=18$

Thus, $x+\left[3\left(y+z\right)-y\right]=18$