Question

Simplify$\left(7x^3{y}^{-5}\right)\left(4x{y}^3\right)$ assuming that no variable equal to 0 .

Short answer

The simplified value of expression is $28x^4{y}^{-2}$.

Step-by-step solution

Step 1. Write down the given expression.

The given expressiomn to simplify is $\left(7x^3{y}^{-5}\right)\left(4x{y}^3\right)$.

Step 2. Simplify the given expression.

Simplifying $\left(7x^3{y}^{-5}\right)\left(4x{y}^3\right)$ gives,

$\begin{array}{c}\left(7x^3{y}^{-5}\right)\left(4x{y}^3\right)=\left(7\right)\left(x^3{y}^{-5}\right)\left(4\right)\left(x{y}^3\right)\mathrm{....}(\text{Using}{x}^a\times x^b=x^{a+b})\\ =(7\times 4){\left(x\right)}^{3+1}{\left(y\right)}^{-5+3}\\ =28x^4{y}^{-2}\end{array}$

Step 3. Conclusion.

The simplified value of expression is $28x^4{y}^{-2}$.