Question

Find $p\left(4\right)\text{and}p\left(-2\right)$ for the function $p\left(x\right)=2x^3-x^2+5x-7$.

Short answer

The value of $p\left(4\right)=125\text{and}p\left(-2\right)=-37$.

Step-by-step solution

Step 1. Write down the given information.

The given function is $p\left(x\right)=2x^3-x^2+5x-7$.

Step 2. Calculation.

Evaluating $p\left(4\right)\text{and}p\left(-2\right)$ by plugging $x=4\text{and}x=-2$ in given function $p\left(x\right)=2x^3-x^2+5x-7$.

$\begin{array}{c}p\left(x\right)=2x^3-x^2+5x-7....\left(\text{Given}\right)\\ p\left(4\right)=2{\left(4\right)}^3-{\left(4\right)}^2+5\left(4\right)-7\\ =125\\ \text{Now,}p\left(-2\right)=2{\left(-2\right)}^3-{\left(-2\right)}^2+5\left(-2\right)-7\\ =-37\end{array}$

Step 3. Conclusion.

The value of $p\left(4\right)=125\text{and}p\left(-2\right)=-37$.