Question

Find $p\left(4\right)\text{and}p\left(-2\right)$ for the function $p\left(x\right)=x^2-3x+8$.

Short answer

The value of $p\left(4\right)=12\text{and}p\left(-2\right)=18$.

Step-by-step solution

Step 1. Write down the given information.

The given function is $p\left(x\right)=x^2-3x+8$.

Step 2. Calculation.

Evaluating $p\left(4\right)\text{and}p\left(-2\right)$by plugging $x=4\text{and}x=-2$ in given function $p\left(x\right)=x^2-3x+8$.

$\begin{array}{c}p\left(x\right)=x^2-3x+8....\left(\text{Given}\right)\\ p\left(4\right)={\left(4\right)}^2-3\left(4\right)+8\\ =12\\ \text{Now,}p\left(-2\right)={\left(-2\right)}^2-3\left(-2\right)+8\\ =18\end{array}$

Step 3. Conclusion.

The value of $p\left(4\right)=12\text{and}p\left(-2\right)=18$.