Question

Find the value of each determinant.

$\left|\begin{array}{cc}6& 14\\ -3& -8\end{array}\right|$

Short answer

The value of the determinant $\left|\begin{array}{cc}6& 14\\ -3& -8\end{array}\right|=-6$.

Step-by-step solution

- Define the determinant of second-order matrix

The determinant of second order matrix is found by calculating the difference of the product of the two diagonals, that is., $\left|\begin{array}{cc}a& b\\ c& d\end{array}\right|=ad-bc$.

- Find the determinant

Apply the definition of the method of finding determinant of second order

matrix $\left|\begin{array}{cc}6& 14\\ -3& -8\end{array}\right|$.

$\left|\begin{array}{cc}6& 14\\ -3& -8\end{array}\right|=6\times \left(-8\right)-\left(-3\right)\left(14\right)$

- Simplify

To further simplify multiply the values first.

$\begin{array}{c}\left|\begin{array}{cc}6& 14\\ -3& -8\end{array}\right|=6\times \left(-8\right)-\left(-3\right)\left(14\right)\\ =-48+\text{42}\\ =-6\end{array}$