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Graph each system and determine a number of solutions that it has. If it has one solution, name it.

2x+3y=42x+3y=1

Short Answer

Expert verified

The graph of the given system of equations is:

The number of solutions that the given system of equations has is zero that implies the given system of equations has no solution.

Step by step solution

01

Step 1. Graph the given system of equations.

The given system of equations is:

2x+3y=42x+3y=1

The equation is: 2x+3y=4

Substitute 0 forx and find the value of y.

2x+3y=42(0)+3y=40+3y=43y=4y=43

Therefore, one of the point is 0,43

Substitute 0 fory and find the value of x.

2x+3y=42x+3(0)=42x=4x=42x=2

Therefore, the other point is (2,0)

Therefore, the graph of the equation 2x+3y=4is the line passing through the points 0,43and (2,0).

The equation is: 2x+3y=1

Substitute 0 forx and find the value of y.

2x+3y=12(0)+3y=13y=1y=13

Therefore, one of the point is 0,13

Substitute 0 for yand find the value of x.

2x+3y=12x+3(0)=12x=1x=12

Therefore, the other point is12,0

Therefore, the graph of the equation2x+3y=1 is the line passing through the points0,13 and 12,0.

Therefore, the graph of the given system of equations is:

02

Step 2. Determine the number of solutions that the given system of equations has.

From the graph of the system of equations, it can be noticed that there is no intersection point of the lines as the lines are parallel lines. Therefore, the given system of equations has no solution.

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