Question

Use a table of values to graph the given equation. State the domain and range.

$y=2x^2-4x+3$

Short answer

The graph of the given function is

The domain is $\left(-\infty ,\infty \right)$and the range is role="math" localid="1647700209891" $[1\mathbf{,}\infty )$.

Step-by-step solution

Step 1. Define the standard form of the quadratic function.

A quadratic function, which is written in the form, $y=a{x}^2+bx+c$, where,$a\ne 0$is called the standard form of the quadratic function.

Step 2. Define the domain and range of a function.

The domain is the set of all of the possible values of the independent variable $x$.

The range is the set of all the possible values of the dependent variable $y$.

Step 3. Calculate the table of values for the function y=2x2−4x+3.

$x$	$y$
$-2$	19
$-1$	9
0	3
1	1
2	3

Step 4. Use the table of values to graph the function y=2x2−4x+3.

Graph the ordered pairs from the table and connect them to create a smooth curve.

Step 5. State the domain and range for function y=2x2−4x+3.

Observe the graph.

The parabola extends to infinity.

So, the domain is $\left(-\infty ,\infty \right)$.

The minimum value of the function is 11.

So, the range is $\left[1\right.,\left.\infty \right)$.

Therefore, the domain is $\left(-\infty ,\infty \right)$and the range is $\left[1\right.,\left.\infty \right)$.