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Solve each inequality. Check your solution.

t36>4

Short Answer

Expert verified

The solution of the given inequalityt36>4 is t>6.

Check:

To perform the check of the solution, substitute a number greater than 6 ast>6in the given inequality t36>4, if the condition obtained is true, the solution is correct and if the condition obtained is false, the solution is incorrect.

Let t=9, as 9>6.

Now substitute 9 for t in the inequality t36>4.

t36>4936>436>43>4

As, the condition obtained3>4 is true, therefore the solution is correct.

Step by step solution

01

Step 1. Write the addition and multiplication property of inequalities. 

The addition property of inequalities states that if the same number is added to each side of a true inequality, the resulting inequality is also true that is:

(i) If a>b, then a+c>b+c.

(ii) If a<b, then a+c<b+c.

The multiplication property of inequalities states that if both sides of the inequality are multiplied by a positive number the sign of the inequality remains the same and if both sides of the inequality are multiplied by a negative number then the sign of the inequality changes that is:

(i) If a>bandc is a positive number then ac>bc.

(ii) If a<b and c is a positive number then ac<bc.

(ii) If a>b and c is a negative number then ac<bc.

(iv) If a<b and c is a negative number then ac>bc.

02

Step 2. Solve the given inequality t3−6>−4.

The solution of the given inequalityt36>4is:

t36>4t36+6>4+6byusingadditionpropertyofinequalityt3>23t3>32byusingmutiplicationpropertyofinequalityt>6

Therefore, the solution of the given inequalityt36>4is width="31">t>6.

03

Step 3. Check the solution.

To perform the check of the solution, substitute a number greater than 6 ast>6 in the given inequality t36>4, if the condition obtained is true, the solution is correct and if the condition obtained is false, the solution is incorrect.

Let t=9, as 9>6.

Now substitute 9 for t in the inequality t36>4.

t36>4936>436>43>4

As, the condition obtained3>4 is true, therefore the solution is correct.

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