Question

Write an equation of a line in slope-intercept form with the given slope and $\mathit{y}$-intercept. Then graph the equation.

Slope:, $\mathit{y}$-intercept: $\mathbf{-}\mathbf{1}$

Short answer

The equation in slope-intercept form is $\mathit{y}\mathbf{=}\frac{\mathbf{3}}{\mathbf{4}}\mathit{x}\mathbf{-}\mathbf{1}$and the graph of the equation is:

Step-by-step solution

Step 1. State the concept of standard form of an equation.

The slope-intercept form of a linear equation is $y=mx+b$, where $m$is the slope and $b$is the $y$-intercept.

Step 2. Write equation of a line in slope-intercept form.

To find the equation of a line in slope-intercept form substitute $\frac{3}{4}$for localid="1647424258169" $m$and localid="1647424252045" $-1$for localid="1647424255110" $b$in the equation localid="1647424248683" $y=mx+b$.

The equation of the straight line is:

$\begin{array}{l}y=mx+b\\ y=\frac{3}{4}x-1\end{array}$

Step 3. Graph the equation.

Plot this equation on the Cartesian plane.

Therefore, the equation of the straight line is $y=\frac{3}{4}x-1$and the graph of the equation is drawn above.