Question

Write an equation of a line in slope-intercept form with the given slope and $\mathit{y}$-intercept. Then graph the equation.

Slope: -5, $\mathit{y}$-intercept: 3

Short answer

The equation in slope-intercept form is $\mathit{y}\mathbf{=}\mathbf{-}\mathbf{5}\mathit{x}\mathbf{+}\mathbf{3}$and the graph of the equation is:

Step-by-step solution

Step 1. State the concept of standard form of an equation.

The slope-intercept form of a linear equation is $y=mx+b$, where $m$is the slope and $b$is the$y$-intercept.

Step 2. Write equation of a line in slope-intercept form.

To find the equation of a line in slope-intercept form substitute $-5$for $m$and 3 for $b$in the equation $y=mx+b$.

The equation of the straight line is:

$\begin{array}{l}y=mx+b\\ y=-5x+3\end{array}$

Step 3. Graph the equation.

Plot this equation on the Cartesian plane.

Therefore, the equation of the straight line is $y=-5x+3$and the graph of the equation is drawn above.