Question

One pencil is randomly selected from a case containing 3 red, 4 green, 2 black, and 6 blue pencils. Find each probability.

$P\left(\text{green}\right)$

Short answer

The probability is $P=0.27$.

Step-by-step solution

Step 1. Formula used.

$\text{Probability}P=\frac{\text{Possibleevent}\left(PE\right)}{\text{Totalevent}\left(TE\right)}$

Step 2. Total numbers of pencils in case.

$\begin{array}{l}TE=3+4+2+6\\ TE=15\end{array}$

Step 3. Calculate the probability of a green pencil when randomly selected.

$\begin{array}{l}\text{Probability}P=\frac{\text{Totalgreenpencil}\left(PE\right)}{\text{Totalnumberofpencil}\left(TE\right)}\\ \text{Probability}P=\frac{4}{15}\\ P=0.27\end{array}$

Therefore, the probability of one green pencil when randomly selected from the case.

$P=0.27$