Question

A solution is prepared by dissolving 24 milliliters of saline in 150 milliliters of pure solution. What is the percent of saline in the pure solution?

Short answer

The percent of saline in pure water is 16%

Step-by-step solution

Step 1. Let x and y be the amount of saline and pure water.

$\begin{array}{l}\text{AmountofSaline}x=\text{24ml}\\ \text{Amountofpurewater}y=150\text{ml}\end{array}$

Step 2. Formula used.

To find what percent is a number x of another number y, use the below formula

$\begin{array}{l}x\text{ispercentof}y=\frac{x\times 100}{y}\%\\ \text{Where}x\text{and}y\text{isintegers}\end{array}$

Step 3. Calculate the percent of saline in pure water.

$\begin{array}{l}\text{Percentofsalineinpurewater}=\frac{24\times 100}{150}\%\\ =\frac{240}{15}\%\\ \text{Percentofsalineinpurewater}=16\%\end{array}$

Therefore, the percent of saline in pure water is 16%