Question

Examples 4 and 5 If$f\left(x\right)=6x+7$ and$g\left(x\right)=x^2-4,$ find each value. (P. 49)

$f(q+1)$

Short answer

The function value at$x=q+1$ is$6q+13$

Step-by-step solution

Step 1. Interpreting of function.

$f\left(q+1\right)$Indicates the value of function$f\left(x\right)$ at$x=q+1$

Step 2. Apply substitution method.

Substitute$x=q+1$ into the function$f\left(x\right)$

$f\left(q+1\right)=6\left(q+1\right)+7$

Step 3. Further calculation:

$\begin{array}{l}f\left(q+1\right)=6q+6+7\\ f\left(q+1\right)=6q+13\end{array}$

Thus, the function value at$x=q+1$ is$6q+13$