Question

Evaluate the expression. $$3 y^{4}+15 y \text { when } y=-0.02$$

Short answer

The evaluated expression is -0.29999952 when \(y = -0.02\).

Step-by-step solution

Substitute y into the first term

Replace \(y\) in the first term of the equation with \(-0.02\). This gives the equation as: \(3(-0.02)^4\).

Calculate the first term

Evaluate the exponent first (according to the BIDMAS or PEMDAS order of operations), then multiply the result by 3. This gives: \(3 * (-0.02)^4 = 3*0.00000016 = 0.00000048\).

Substitute y into the second term

Replace \(y\) in the second term of the equation with \(-0.02\). This gives the equation as: \(15 * -0.02\).

Calculate the second term

Calculate the product of 15 and -0.02. This gives: \(15 * -0.02 = -0.3\).

Add the results

Add the resulting values of the first term and the second term. This gives: \(0.00000048 + -0.3 = -0.29999952\).