Question

The table shows the number of shutouts that ten baseball pitchers had in their careers. A shutout is a complete game pitched without allowing a run. $$\begin{array}{|I|l|c|c|}\hline \text { Pitcher } & \text { Shutouts } \\\\\hline \text { Warren Spahn } & \text { 63 } \\\\\hline \text { Christy Mathewson } & 80 \\\\\hline \text { Eddie Plank } & 69 \\\\\hline \text { Nolan Ryan } & 61 \\\\\hline \text { Bert Blyleven } & 60 \\\\\hline \text { Don Sutton } & 58 \\\\\hline \text { Grover Alexander } & 90 \\\\\hline \text { Walter Johnson } & 110 \\\\\hline \text { Cy Young } & 76 \\\\\hline \text { Tom Seaver } & 61 \\\\\hline\end{array}$$ Find the mean and the median for the set of data.

Short answer

The mean of the data set is 71.8, and the median is 66.

Step-by-step solution

Identify the data

List the given data in ascending order for ease of calculations. The list of shutouts is: 58, 60, 61, 61, 63, 69, 76, 80, 90, 110.

Calculate the mean

Add up all the numbers and then divide by the count of numbers. In this case, \( \text{mean} = \frac{58 + 60 + 61 + 61 + 63 + 69 + 76 + 80 + 90 + 110}{10} = \frac{718}{10} = 71.8 \)

Calculate the median

In a set of sorted data with 10 numbers (even numbers), the median is the average of the 5th and 6th number. In this case, \( \text{median} = \frac{63 + 69}{2} = \frac{132}{2} = 66\)