Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write an equation in slope-intercept form of the line that passes through the points. $$ \left(\frac{1}{4}, 2\right),\left(-5, \frac{2}{3}\right) $$

Short Answer

Expert verified
The final equation of the line that passes through the points (1/4, 2) and (-5, 2/3) can be obtained by substituting the calculated slope 'm' and y-intercept 'b' into the slope-intercept form \( y = m*x + b \).

Step by step solution

01

Calculate the Slope

The slope 'm' of a line that passes through two points (x1, y1) and (x2, y2) is given by: \( m = \frac{y2 - y1}{x2 - x1} \) Here, (x1, y1) is (1/4, 2) and (x2, y2) is (-5, 2/3). Substituting these values into the formula gives: \( m = \frac{2/3 - 2}{-5 - 1/4} \) Simplifying this expression will give the calculated slope.
02

Calculate the Y-Intercept

Once the slope 'm' is known, it can be substituted back into the slope-intercept equation, along with the coordinates of one of the points, to find the y-intercept 'b'. The equation is given by: \( b = y1 - m*x1 \) Substitute y1 = 2, x1 = 1/4 and 'm' as the calculated slope into the equation, and simplify the expression to find the value of 'b'.
03

Write the Equation of the Line

After calculating the slope 'm' and the y-intercept 'b', substitute these values into the slope-intercept form. The final equation of the line will be: \( y = m*x + b \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free