Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Use a table of values to graph the equation. \(y=-\frac{3}{4} x+1\)

Short Answer

Expert verified
The graph of the equation \(y = -\frac{3}{4}x + 1\) is a straight line that slopes downward from left to right, intersecting the y-axis at y=1. This was confirmed after plotting the points (-2, 2.5), (0, 1), and (2, -0.5) obtained from our table of values.

Step by step solution

01

Identify the slope and y-intercept

The equation provided is \(y = -\frac{3}{4}x + 1\). Here, the number in front of x (-3/4) is the slope (m), and the constant at the end of the equation (1) is the y-intercept (b). Thus, for every 4 units that x increases, y will decrease by 3 units, and when x=0, y=1.
02

Construct a table of values

Choose a range of x values. For example, [-2, 0, 2]. Now substitute each x value into the equation to find the corresponding y value. For x=-2, substituting into the equation gives \(y = -\frac{3}{4}*(-2) + 1 = 2.5\). For x=0, \(y = -\frac{3}{4}*0 + 1 = 1\). For x=2, substituting gives \(y = -\frac{3}{4}*2 + 1 = -0.5\). Our table of values is thus as follows: (-2, 2.5), (0, 1), (2, -0.5).
03

Plot the points on a graph

The coordinate pairs from the table of values become points on the graph. Plot these points and draw a straight line through them. The line represents the equation. When you've plotted points (-2, 2.5), (0, 1), and (2, -0.5), a downward sloping straight line will emerge, which is accurate given the negative slope (-3/4) of the equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free