Question

Evaluate the expression for the given value(s) of the variable(s). $$\frac{15 x^{2}+10}{y} \text { when } x=-3 \text { and } y=\frac{2}{3}$$

Short answer

The evaluated expression when \(x=-3\) and \(y=\frac{2}{3}\) equals 217.5

Step-by-step solution

Substitute the given values

The first step is to substitute x with -3 and y with \(2/3\) in the expression \(\frac{15 x^{2}+10}{y}\). Doing so, we get: \(\frac{15*(-3)^{2}+10}{2/3}\)

Simplify Above Expression

Now simplify the equation. Solve for \((-3)^{2}\) which gives 9, then multiply 15 by 9 and add 10. This gives: \(\frac{15*9+10}{2/3} = \frac{145}{2/3}\)

Simplification

Now divide 145 by \(2/3\). Since dividing by a fraction is the same as multiplying by its reciprocal, it gives: \(145 * \frac{3}{2} = 217.5\)