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Decide whether the ordered pair is a solution of the inequality. $$y \leq 2 x^{2}-3 x+10 ;(-2,20)$$

Short Answer

Expert verified
Yes, the ordered pair (-2,20) is a solution to the inequality.

Step by step solution

01

Substitute for x and y

Substitute -2 for x and 20 for y in the inequality \(y \leq 2 x^{2}-3 x+10\). The inequality becomes: \(20 \leq 2 (-2)^{2}-3 (-2)+10\).
02

Simplify the Right Side

Compute the right side: \(2 (-2)^{2}-3 (-2)+10 = 2 \cdot 4 + 6 + 10 = 24.\) The inequality now is \(20 \leq 24\).
03

Verify the Inequality

As 20 is less than or equal to 24, hence, the inequality is true.

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