Chapter 12: Problem 31
Solve the equation. Check for extraneous solutions. $$\sqrt{\frac{1}{5} x-2}-\frac{1}{10}=\frac{7}{10}$$
Chapter 12: Problem 31
Solve the equation. Check for extraneous solutions. $$\sqrt{\frac{1}{5} x-2}-\frac{1}{10}=\frac{7}{10}$$
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Get started for freeWhat is the midpoint between \((-2,-3)\) and \(\left(1, \frac{1}{2}\right) ?\) \(\begin{array}{llll}\text { (A) }\left(-1,-2 \frac{1}{2}\right) & \text { (B }\left(-\frac{1}{2},-2 \frac{1}{2}\right) & \text { C }\left(-1,-1 \frac{1}{4}\right) & \text { \odot }\left(-\frac{1}{2},-1 \frac{1}{4}\right)\end{array}\)
Find the midpoint between the two points \((5,-5),(-5,1)\)
Find the midpoint between the two points \((-1,1),(-4,-4)\)
Decide whether the ordered pair is a solution of the inequality. $$y<3 x^{2}-2 x ;(5,10)$$
Solve the equation. Check for extraneous solutions. $$\sqrt{\frac{1}{9} x+1}-\frac{2}{3}=\frac{5}{3}$$
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