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Describe the square root function.

Short Answer

Expert verified
The square root function \(f(x) = \sqrt{x}\), is only defined for \(x \geq 0\) and gives the square root of \(x\) as output. Its properties include a domain and range of \([0, \infty)\) and a graph that is a rising curve starting at the origin. Common square roots to know include \(\sqrt{1} = 1\), \(\sqrt{4} = 2\), \(\sqrt{9} = 3\), \(\sqrt{16} = 4\).

Step by step solution

01

Definition of Square Root Function

The square root function is a type of radical function, which is defined as \(f(x) = \sqrt{x}\). This function takes an input value, known as \(x\) and gives as output the square root of \(x\). The square root of a number \(x\) is the number that, when squared (multiplied by itself), equals \(x\).
02

Properties of the Square Root Function

1) The square root function is only defined for \(x \geq 0 \), since the square root of a negative number is not a real number, it is an imaginary number. This means the domain of \(f(x) = \sqrt{x}\) is \([0, \infty)\). \n 2) The output of the square root function is always either positive or zero. This means the range of \(f(x) = \sqrt{x}\) is \([0, \infty)\). \n 3) The graph of the square root function is a rising curve starting at the origin (0,0). It rises more slowly as x increases.
03

Common Square Root Values

\(\sqrt{1} = 1\), since \(1^2 = 1\). \n \(\sqrt{4} = 2\), since \(2^2 = 4\). \n \(\sqrt{9} = 3\), since \(3^2 = 9\). \n \(\sqrt{16} = 4\), since \(4^2 = 16\). These values should be easily recognized.

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