Question

Evaluate the function for \(x=0,1,2,3,\) and 4. $$f(x)=-x+9 \quad$$

Short answer

The function \(f(x) = -x + 9\) evaluates to 9, 8, 7, 6, and 5 for \(x = 0, 1, 2, 3, 4\) respectively.

Step-by-step solution

Initialization

The function is given by \(f(x) = -x + 9\). We will evaluate this function for \(x = 0, 1, 2, 3, 4\).

Evaluate \(f(x)\) at \(x=0\)

Replace \(x\) in \(f(x) = -x + 9\) with 0 to find \(f(0) = -(0) + 9 = 9\). So, when \(x = 0\), \(f(x) = 9\).

Evaluate \(f(x)\) at \(x=1\)

Replace \(x\) in \(f(x) = -x + 9\) with 1 to find \(f(1) = -(1) + 9 = 8\). So, when \(x = 1\), \(f(x) = 8\).

Evaluate \(f(x)\) at \(x=2\)

Replace \(x\) in \(f(x) = -x + 9\) with 2 to find \(f(2) = -(2) + 9 = 7\). So, when \(x = 2\), \(f(x) = 7\).

Evaluate \(f(x)\) at \(x=3\)

Replace \(x\) in \(f(x) = -x + 9\) with 3 to find \(f(3) = -(3) + 9 = 6\). So, when \(x = 3\), \(f(x) = 6\).

Evaluate \(f(x)\) at \(x=4\)

Replace \(x\) in \(f(x) = -x + 9\) with 4 to find \(f(4) = -(4) + 9 = 5\). So, when \(x = 4\), \(f(x) = 5\).