Chapter 11: Problem 26
Solve the proportion. Check for extraneous solutions. $$\frac{5}{2 y}=\frac{7}{y-3}$$
Chapter 11: Problem 26
Solve the proportion. Check for extraneous solutions. $$\frac{5}{2 y}=\frac{7}{y-3}$$
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Get started for freeWrite the equation in standard form. (Lesson 9.5 for 11.7 ) $$6 x^{2}=5 x-7$$
Find the LCD of \(\frac{-2}{x+9}\) and \(\frac{5 x}{x^{2}+9 x}\) (A) \(\frac{x-1}{(x-1)(2 x+1)}\) \((\mathbf{B})-\frac{x}{x-1}\) (c) \(\frac{2 x^{2}+1}{(x-1)(2 x+1)}\) (D) \(\frac{2 x^{2}-1}{(x-1)(2 x+1)}\)
Simplify the expression \(\frac{x}{x-1}-\frac{1}{2 x+1}\) (A) \(\frac{x-1}{(x-1)(2 x+1)}\) (B) \(-\frac{x}{x-1}\) (C) \(\frac{2 x^{2}+1}{(x-1)(2 x+1)}\) (D) \(\frac{2 x^{2}-1}{(x-1)(2 x+1)}\)
You will write and simplify a general expression for the average speed traveled when making a round trip. Let \(d\) represent the one-way distance. Let \(x\) represent the speed while traveling there and let \(y\) represent the speed while traveling back. What do you notice about the variables in the final answer? If your distance is doubled what happens to the average speed?
Completely factor the expression. $$6 x^{2}+16 x$$
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